Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
The formula mass of calcium acetate (Ca(C2H3O2)2) is calculated by adding the atomic masses of all the atoms in the formula. For calcium acetate, the atomic masses are: Ca (40.08 g/mol) + 2(C) + 3(H) + 2(O). By adding these values, the formula mass for calcium acetate is calculated to be 158.17 g/mol.
To calculate the formula mass of Na3NO2, we need to add the atomic masses of each atom in the compound. Na (sodium) has a mass of 22.99 g/mol, N (nitrogen) has a mass of 14.01 g/mol, and O (oxygen) has a mass of 16.00 g/mol. Therefore, the formula mass of Na3NO2 = 3(Na) + 1(N) + 2(O) = 3(22.99) + 14.01 + 2(16.00) = 85.97 g/mol.
Barium is in Group 2, so we know that it makes 2+ ions. If you happen to have a chart of common polyatomic ions, you can find out that phosphate is PO4 and has a 3- charge. So, to even out the charges, we need to get three barium ions and two phosphate ions. Now, the total positive charge (from the barium ions) is 6+, and the total negative charge (from the phosphate ions) is 6-.We see that Ba3(PO4)2 is the chemical formula for barium phosphate.
The formula mass of aluminum oxide (Al2O3) is approximately 102 atomic mass units.
The formula mass of Ca3(PO4)2 is 3(40.1) + 2[31.0 + 4(16.0)] = 310.3 The atomic masses of the individual elements can be obtained from the perodic table.
399.91 amu Fe(2*55.85)+S(3*32.07)+O(12*16.00)
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
The formula mass of calcium acetate (Ca(C2H3O2)2) is calculated by adding the atomic masses of all the atoms in the formula. For calcium acetate, the atomic masses are: Ca (40.08 g/mol) + 2(C) + 3(H) + 2(O). By adding these values, the formula mass for calcium acetate is calculated to be 158.17 g/mol.
To calculate the formula mass of Na3NO2, we need to add the atomic masses of each atom in the compound. Na (sodium) has a mass of 22.99 g/mol, N (nitrogen) has a mass of 14.01 g/mol, and O (oxygen) has a mass of 16.00 g/mol. Therefore, the formula mass of Na3NO2 = 3(Na) + 1(N) + 2(O) = 3(22.99) + 14.01 + 2(16.00) = 85.97 g/mol.
To calculate the formula mass of Al2(SO4)3, we need to determine the molar masses of each element and multiply them by the respective subscripts in the formula. The molar mass of aluminum (Al) is 26.98 g/mol, sulfur (S) is 32.06 g/mol, and oxygen (O) is 16.00 g/mol. Therefore, the formula mass of Al2(SO4)3 is 2(26.98) + 3(32.06 + 4(16.00)) = 342.15 g/mol.
Calcium acetate, or Calcium ethanoate, has the molecular formula (CH3COO)2Ca. The atomic weights of Carbon, Hydrogen, Oxygen and Calcium are 12, 1, 16 and 40, respectively. So, the formula mass is 2 x ((1 x 12) + (3 x 1) + (2 x 16)) + (1 x 40) = 134
the density of an object that is 10 cm by 2 cm and has a mass 400g will be 10000 Kg m-3. This can be calculated by the formula, density = mass/volume
The gram formula unit mass of the empirical formula C2H3 is twice the gram atomic mass of carbon plus three times the gram atomic mass of hydrogen, or about 27. The nearest integer to 162.27/27 is 6. Therefore, the molecular formula for the compound is C12H18.
Barium is in Group 2, so we know that it makes 2+ ions. If you happen to have a chart of common polyatomic ions, you can find out that phosphate is PO4 and has a 3- charge. So, to even out the charges, we need to get three barium ions and two phosphate ions. Now, the total positive charge (from the barium ions) is 6+, and the total negative charge (from the phosphate ions) is 6-.We see that Ba3(PO4)2 is the chemical formula for barium phosphate.
Because an empirical formula is the simplest form of a compound, we know that the molecular formula contains more atoms than it does. Since we are given the molar mass, we can use this formula. x ( MM of empirical formula ) = MM of molecular formula MM of empirical formula = 12(2) + 1(6) + 16 = 46 MM of molecular formula = 138 46x = 138 x= 138 / 46 x=3 Therefore, the molecular formula is 3(C2H6O) that is C6H18O3
Molar (formula) mass of calcium nitrate is 164,1 9/mol Molecular weight calculation: 40.078 + (14.0067 + 15.9994*3)*2