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We, Know for any electromagnetic wave(or light)

c=f*l

where,

c=speed of that wave(or light)=3*10^8 m/s

f=frequency of the wave

l=wavelength of the wave

for the given case, l=600 nm=6*10^-7 m

So, Frequence f=c/l=5*10^14 Hz

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12y ago
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14y ago

All light travels in the speed of light in vacuum, that is 300,000 km/sec. The relevant formula is C = f*lambda, where C is the speed of light, f is the frequency and lambda the wavelength. Therfore, f = C/lambda. Here lambda = 632.8nm, so f = 4.741E14 or 474 terahertz.

The color of this light, incidentally, is red. Please see the links. They are beautiful, anyway.

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11y ago

"The frequency of an atom" is a rather blurry concept. We'll be much better off

if we simply concentrate our attention on the photon.

Frequency = speed/wavelength = 300,000,000/265 x 10-9 = 1.13 x 1015 Hz

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10y ago

Frequency = speed/wavelength = 3 x 108/510 x 10-9 = 5.88235 x 1014 = 588,000 GHz (rounded)

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6y ago

Convert that to meters. Then divide the speed of light (in meters/second) by the wavelength. The answer will be in hertz.

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12y ago

4.87e14 Hertz

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10y ago

4.979*1014 s

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12y ago

Red (visible) light

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12y ago

457 nm

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Q: What is the frequency of an atom who emits a photon of light having wavelength 615 nm.?
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