RR since sickle cell is a recessive so a dominant trait means a non sicklier. If they have the trait it will be Rr which is heterozygous but RR is homozygous non sicklier.
There can be 4 different non-repeating allele combinations in the gametes of a person with genotype AABBCc: ABC, ACB, BAC, and BCA.
if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children
The circled offspring's genotype will contain the specific genetic traits that were circled or highlighted in their genetic makeup. In contrast, the non-circled offspring's genotype will not have those specific circled genetic traits. This indicates that the circled offspring has inherited or carries those highlighted traits, while the non-circled offspring does not.
To predict the genotypic and phenotypic ratios, we first need to establish the alleles for boldness. Let's assume boldness (B) is dominant and non-boldness (b) is recessive. If the mother is bold, she could be either homozygous (BB) or heterozygous (Bb). If the father is not bold, he is homozygous recessive (bb). If the mother is BB, all offspring will be bold (100% phenotypically bold, BB genotype). If the mother is Bb, the offspring will have a genotypic ratio of 1 BB: 1 Bb (100% bold), resulting in a phenotypic ratio of 100% bold. In summary, regardless of the mother's genotype, all offspring will exhibit the bold phenotype.
Homozygous yellow peas have two identical alleles for yellow color (YY), while heterozygous yellow peas have one yellow allele and one non-yellow allele (Yy). This means that homozygous yellow peas will always produce yellow offspring when crossed, while heterozygous yellow peas have a 50% chance of producing non-yellow offspring when crossed with another heterozygous pea plant.
There can be 4 different non-repeating allele combinations in the gametes of a person with genotype AABBCc: ABC, ACB, BAC, and BCA.
if a man were non- hemophiliac and he marries a woman whois homozygus for nan-hemophilia,give the possible genotypes of the children
The circled offspring's genotype will contain the specific genetic traits that were circled or highlighted in their genetic makeup. In contrast, the non-circled offspring's genotype will not have those specific circled genetic traits. This indicates that the circled offspring has inherited or carries those highlighted traits, while the non-circled offspring does not.
To predict the genotypic and phenotypic ratios, we first need to establish the alleles for boldness. Let's assume boldness (B) is dominant and non-boldness (b) is recessive. If the mother is bold, she could be either homozygous (BB) or heterozygous (Bb). If the father is not bold, he is homozygous recessive (bb). If the mother is BB, all offspring will be bold (100% phenotypically bold, BB genotype). If the mother is Bb, the offspring will have a genotypic ratio of 1 BB: 1 Bb (100% bold), resulting in a phenotypic ratio of 100% bold. In summary, regardless of the mother's genotype, all offspring will exhibit the bold phenotype.
no person is irrational no person is non-irrational no non-irrational is person every non-irrational is non-person some non-person is non-irrational some non-person is not irrational
no person is irrational no person is non-irrational no non-irrational is person every non-irrational is non-person some non-person is non-irrational some non-person is not irrational
Homozygous yellow peas have two identical alleles for yellow color (YY), while heterozygous yellow peas have one yellow allele and one non-yellow allele (Yy). This means that homozygous yellow peas will always produce yellow offspring when crossed, while heterozygous yellow peas have a 50% chance of producing non-yellow offspring when crossed with another heterozygous pea plant.
We'llsay F is dominant for freckles and f is recessive for non-freckled. The father is ff The mother is Ff The child is ff. Probability of this cross producing a homozygous recessive child is 50%. There isn't a precise term for this cross.
Thw genetic make-up, is the sequence of nucleic acids, Guanine, Adenine, Thymine, and Cytosine , that make up everything about you.("'\(o.o)/"')
To provide an accurate phenotype ratio, we need to know the specific traits being analyzed (such as eye color) and the genetic makeup of the heterogeneous male (e.g., whether he is homozygous or heterozygous for a specific trait). Assuming we're looking at a simple trait like eye color where pink is recessive, if the male is heterozygous (Pp) and the female is homozygous recessive (pp), the offspring would have a phenotype ratio of 1:1 (1 pink-eyed to 1 non-pink-eyed). If the male's genotype is different, the ratio may vary accordingly.
The genotype that best describes heterozygous inflated is typically represented as "I/i," where "I" denotes the allele for inflated pods and "i" represents the allele for non-inflated pods. In this case, the individual carries one allele for inflated pods and one for non-inflated, exhibiting the dominant trait of inflated pods. This heterozygous condition results in the expression of the inflated phenotype.
The name for a person who writes non-fiction is a non-fiction author or writer.