The genotype of the offspring with yellow pods is likely homozygous dominant (YY) or heterozygous (Yy), assuming yellow pods are dominant over green. The possible genotypes of the offspring with green pods would be homozygous recessive (yy), as green is the recessive trait. If both yellow-podded parents are heterozygous (Yy), some offspring could also be yellow (YY or Yy) while others could be green (yy).
Since smooth yellow peas are dominant traits (represented by genotypes RRYY or RRYy), all offspring from a cross between two plants with smooth yellow peas will also have smooth yellow peas. Therefore, 100% of the offspring will have this phenotype.
BBEe and bbEe. Black is dominant, and brown is recessive. Yellow is also recessive. Because one parent is brown, for none of the puppies to also be brown the black parent cannot carry the recessive allele on the B locus. Because neither parent is yellow but some of the puppies are, both parents must carry the recessive allele on the E locus.
This is one of the classic experiments carried out by Gregor Mendel. If you cross pure-breeding green pod plants with pure-breeding yellow pod plants the offspring (F1 generation) will all have green pods. This means that green pod is dominant and yellow pod is recessive. To explain the results, pure-breeding green pod plants must have the genotype GG (homozygous dominant) and yellow pod plants must be gg (homozygous recessive). When they are crossed the F1 offspring will receive a G allele from the green parent and a g allele from the yellow parent, so they will all have the genotype Gg ie they will be heterozygous.
The possible phenotypes of the offspring from a cross between yellow and red parental plants depend on the inheritance pattern of the traits. If yellow is dominant over red, the offspring could display either yellow or red phenotypes, with yellow being more prevalent. If the traits follow incomplete dominance, the offspring might show a blend of the two colors, resulting in orange. The exact phenotypic ratios would also depend on whether the parental plants are homozygous or heterozygous for their respective colors.
Identify the genotype trait of the seed color is yellow or green?
25%
Gk, gk
Since smooth yellow peas are dominant traits (represented by genotypes RRYY or RRYy), all offspring from a cross between two plants with smooth yellow peas will also have smooth yellow peas. Therefore, 100% of the offspring will have this phenotype.
In pea plants, the yellow color (Y) is typically dominant over the green color (y). If a heterozygous yellow pea plant (Yy) is crossed with a green pea plant (yy), the possible genotypes of the offspring would be 50% heterozygous yellow (Yy) and 50% homozygous green (yy). Therefore, the offspring would exhibit a 50% chance of being yellow and a 50% chance of being green.
The parents were likely both heterozygous for seed color, with genotypes of Yy. This would result in a 3:1 phenotypic ratio of yellow to green seeds in the offspring, consistent with the observed 93:31 ratio.
The reason why short plants reappeared in Mendel's F2 generation of pea plants was because their short trait was heterozygous. Both parents carriedÊthat recessive gene, so they passed it on to their offspring.
BBEe and bbEe. Black is dominant, and brown is recessive. Yellow is also recessive. Because one parent is brown, for none of the puppies to also be brown the black parent cannot carry the recessive allele on the B locus. Because neither parent is yellow but some of the puppies are, both parents must carry the recessive allele on the E locus.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
When crossing two heterozygous pea plants (Yy x Yy) using a Punnett square, the resulting genotypes are YY, Yy, Yy, and yy. This results in a 1:2:1 genotype ratio, where 25% of the offspring will be homozygous dominant (YY), 50% will be heterozygous (Yy), and 25% will be homozygous recessive (yy). The phenotypic ratio will be 3 yellow (YY and Yy) to 1 green (yy).
This is one of the classic experiments carried out by Gregor Mendel. If you cross pure-breeding green pod plants with pure-breeding yellow pod plants the offspring (F1 generation) will all have green pods. This means that green pod is dominant and yellow pod is recessive. To explain the results, pure-breeding green pod plants must have the genotype GG (homozygous dominant) and yellow pod plants must be gg (homozygous recessive). When they are crossed the F1 offspring will receive a G allele from the green parent and a g allele from the yellow parent, so they will all have the genotype Gg ie they will be heterozygous.
The possible offspring of green and yellow pods receive half of their DNA from each parent. This is through the process of genetic recombination during sexual reproduction, where genetic material from both parents combines to create a unique combination in the offspring.
The botanist could perform test crosses between the green-pod plant and a known homozygous recessive individual. If all offspring show the dominant green pod trait, the green-pod plant is likely homozygous. If the offspring display a mix of green and yellow pods, the green-pod plant is most likely heterozygous.