25%
Because a cow only produces one offspring at a time, not several like mice, cats, dogs, flies or frogs do. In order to have a successful test cross, the species of animal used must have at least 10 to 20 offspring to study from.
Yes, mother cats do mate with their offspring. I had cat which had become so old that my family members used to call her grandmother cat. I had once seen her mating with her offspring and THEIR offspring at different times!
A broodstag is a young rooster with a particular bloodline that is ideal for mating purposes. But being still a Stag, it is not yet proven in terms of producing quality offspring.
Okapis are simply mammals and mate as such. They produce offspring by mating through sexual intercourse and then the mother gives birth to live young after about five months of pregnancy.
Yes although the offspring of such a mating would be inbred which tends to lead to problems. Normally, if the population of deer is large enough in an area, inbreeding isn't too much of an issue though.
In mice the YY genotype is lethal during embryonic development. This means that the mating of heterozygous individuals will produce a ratio of 2:1 Yy to yy offspring.A 'YY' genotype is homozygous dominant for that particular trait. If it is Yy, it will be heterozygous.
AA (dominant) mating with aa (recessive) -----> Aa
Make a Punnet Square:White HETEROZYGOUS---WwRed HOMOZYGOUS--ww (this one is recessive because the white characteristic dominated in the heterozygous type)So:W ww Ww www Ww wwThese four are the potential types of the offspring, they will either be HETEROZYGOUS WHITE or HOMOZYGOUS RED, no homozygous white
NO, because a dominant phenotype could either be homozygous or a heterozygous.so unless you are sure about the genotype of parents we can't determine it...but we can determine the genotype of a person showing reccessive phenotype, as a recessive trait always expresses itself in a homozygous condition...
Probability is the term for the chance that any specific genotype will occur in the offspring from the mating of parents. Typically the capital letter A (in this example) represents the dominant allele as opposed to the recessive allele. The probability of the possible genotypes in a monohybrid cross is 1AA:2Aa:1aa. The probability of AA is .25 or 25%.
A dominant trait, when present, is always expressed. So if the offspring of a red eyed and blue eyed mating are all red, then red must be dominant because it is the trait expressed.
A dominant trait, when present, is always expressed. So if the offspring of a red eyed and blue eyed mating are all red, then red must be dominant because it is the trait expressed.
Because a cow only produces one offspring at a time, not several like mice, cats, dogs, flies or frogs do. In order to have a successful test cross, the species of animal used must have at least 10 to 20 offspring to study from.
The offspring blood type with parents that have O and B blood types would come out with O positive. This is taught in biology. Based on the details of the question this initial answer is incorrect. Type O is not a dominant characteristic merely a common one. A person with type B blood could have a genotype of BO or BB so there are two potential answers to this question. The parent with O type blood can only have an OO genotype. If the parents are BB and OO then all offspring will be type B phenotypically and their genotype will be BO. If the parents are BO and OO then 50% of the offspring will have the BO genotype and 50% will have the OO genotype. Phenotypes will be B and O respectively. Since the question did not include any mention of the RH factor there is no way to determine that the offspring would be positive or negative. True codominance in blood types really only shows up with the AB genotype where the phenotype of the individual matches the genotype and the person has both A and B blood factors.
Test Cross.
An example of a punnet square is if you have the heterozygous Bb genotype. The punnet square would have a big B and a little B at the top and on the side. The first square would be BB, the second one would be Bb, the third would be Bb, and the fourth would be bb. the possibility that the child has the bb genotype is 1/4.
By mating