12 inches
30.5 centimeters
305 millimeters
Let the length of the rectangle be ( L ) feet. Then the width is ( L - 5 ) feet. The area of the rectangle can be expressed as ( L \times (L - 5) = 546 ). Solving the equation ( L^2 - 5L - 546 = 0 ) using the quadratic formula gives ( L = 27 ) feet (the positive solution). Thus, the length of the rectangle is 27 feet.
Let the length of the rectangle be represented by ( l ). Then, the width can be expressed as ( w = l - 6 ). The area ( A ) of the rectangle is given by the product of its length and width, so ( A = l \times w = l \times (l - 6) ). This simplifies to the quadratic function ( A(l) = l^2 - 6l ).
Area = L*B where L = Length, B = Breadth. both given in feet So Area = 17.5 * 11.75 = 205.625 sq inches
Measure the length of the room. We'll call this length "L" Measure the width of the room. We'll call this width "W" Measure the height of the room. We'll call this height "H" Volume = L * W * H
85 decilites = 850 litres1 declitre = 10 L
Area = length * width 120 = L * 10 L = 120/10 = 12 feet
Assuming that the length is at least as great as the width, the length can have any value, L, between 25 and 50 feet. The width, W, then would be 50 - L feet.
L + W = P/2 = 72 feet L = 3W so L = 3/4 x 72 = 54 feet
A = W x L Width = 300 divided by L (or W = 300/L)
Anything you like as long as one of them is greater than or equal to sqrt(409). Let L be any length greater than sqrt(409) feet and let B = 409/L feet Then L*B = L*(409/L) = 409 sq feet.
Assume it is a rectangular window (why?) Suppose the width is L feet. Then the width is L + 3 feet (Odd, because normally Length is the larger of the two) So Perimeter is 2(Length + Width) ie 38 = 2*(L + L+3) 19 = 2L + 3 16 = 2L L = 8 and then L + 3 = 11 So the window is 8 feet long and 11 feet wide.
Area = Length * Width 300 sq ft = L ft * W ft So W = 300/L ft
32
The length of the side of a cube in cm that has a volume of 44.4 L is: 1.162 feet
Well, honey, if the perimeter of a rectangle is 204 feet and the width is 45 feet, you can find the length by using the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Plug in the values and solve for l. In this case, the length of the yard would be 57 feet.
Perimeter = l + l + w + w, where l is the length and w is the width.P = 2l + 2wIn this case: 70 = 2(2) + 2w70 = 4 + 2w66 = 2ww = 33So the width of the rectangle is 33 feet.
1. If you measure the diameter and length in feet. the formula is below. L = length d= Diameter units are in feet # gallons = (L*pi*d2)*1.87 2. if you measure Diamter and Length in inches # gallons = (L*pi*d2)*57.75