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When a charged particle enters in a uniform magnetic field then its kinetic energy ..becomes?
When a charged particle enters a uniform magnetic field, its kinetic energy remains constant. This is because the magnetic field exerts a force perpendicular to the particle's velocity, which changes the direction of the particle's motion but does not work on it. As a result, the speed of the particle—and thus its kinetic energy—remains unchanged, leading to circular or helical motion.
Uniform electric and magnetic fields are acting along the same direction in certain regionIf electron is projected along direction of fields with certain velocity then wats the motion of electron?
When an electron is projected along the direction of uniform electric and magnetic fields, it experiences a force due to the electric field, which accelerates it in the direction of the field. The magnetic field, however, exerts a force that is perpendicular to both its velocity and the magnetic field, causing the electron to undergo circular motion. The net effect is that the electron will spiral along the direction of the fields, with its speed increasing due to the electric field while also being influenced by the magnetic field's perpendicular force. Ultimately, the electron's trajectory will be a helical path along the direction of the fields.
Two identical charged particles moving with same speed enter a region of uniform magnetic field If one of these enters normal to the field direction and the other enters along a direction at 30 with?
So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field. In the first case @ = 90 deg. As sin90 = 1 the force is Bqv. In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv. Hence the force on the latter will be half of that on the earlier one.
A particle with a mass of 6.64 x 10-27 kg and a charge of plus 3.20 x 10-19 C is accelerated from rest through a potential difference of 2.45 x 106 V The particle then enters a uniform 1.60-T magnetic?
The kinetic energy gained by the particle due to the potential difference can be calculated using the formula KE = qV, where q is the charge and V is the potential difference. The kinetic energy can then be equated to the work done by the magnetic field, given by W = qvBd, where v is the velocity, B is the magnetic field, and d is the distance traveled in the magnetic field. Combining these equations can help determine the speed of the particle as it enters the magnetic field.
How do you find distance with uniform velocity time final velocity and initial velocity?
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
When a charged particle enters in a uniform magnetic field then its kinetic energy ..becomes?
When a charged particle enters a uniform magnetic field, its kinetic energy remains constant. This is because the magnetic field exerts a force perpendicular to the particle's velocity, which changes the direction of the particle's motion but does not work on it. As a result, the speed of the particle—and thus its kinetic energy—remains unchanged, leading to circular or helical motion.
What are examples of parabolas in physics?
A mass shot at an angle in a uniform gravitational field and a charged particle shot at an angle through a uniform electric field. The mass and the particle in their respective situations will both follow the path of a parabola (both will have a constant velocity perpendicular to the field and a constantly changing velocity parallel to the field).
When does a particle in motion have non-uniform velocity?
That simply means that its velocity is changing.
Why do electrons in a uniform magnetic field travel in a circular path?
It's because of how magnetic force is. The magnetic force is always perpendicular to both the magnetic field and the velocity of the electron, or any charged particle. If you draw x's on a piece of paper, representing the direction of the magnetic field into the paper, then draw a short vertical line up, representing the electron velocity, the magnetic force will be horizotal to the right. This causes the velocity to change direction a little toward the right. But now the force must change direction a little, etc., etc, until you get a circular path. BTW, you only get a circular path if the initial velocity is in the plane of the paper, perpendicular to the field. If the electron comes in at an angle from outside the paper the path will be a "screw" shape, circular and forward at the same time.
Which of the two an alpha particle or a proton projected normal to a uniform magnetic field would describe a path of smaller radius?
Assuming equal velocity. The alpha particle has twice the charge but four times the mass so it would have the wider radius.
How you find answers of aipmt2008?
a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be
Consider a particle moving with constant speed such that its acceleration of constant magnitude is always perpendicular to its velocity?
Centripetal force is a force that makes a body follow a curved path: it is always directed orthogonal to the velocity of the body, toward the instantaneous center of curvature of the path. - See more at: http://www.chacha.com/question/what-is-the-path-of-a-moving-body-whose-acceleration-is-constant-in-magnitude-at-all-times-and-is-perpendicular-to-the-velocity#sthash.pqrkWxfT.dpuf
Is it true or false that For a particle in uniform circular motion the instantaneous-acceleration vector is directed radially outward?
True. In uniform circular motion, the particle's velocity is tangential to the circular path, and the acceleration is directed radially inward, towards the center of the circular path. This centripetal acceleration causes the change in direction of the particle's velocity, but the magnitude of the velocity remains constant.
Uniform electric and magnetic fields are acting along the same direction in certain regionIf electron is projected along direction of fields with certain velocity then wats the motion of electron?
When an electron is projected along the direction of uniform electric and magnetic fields, it experiences a force due to the electric field, which accelerates it in the direction of the field. The magnetic field, however, exerts a force that is perpendicular to both its velocity and the magnetic field, causing the electron to undergo circular motion. The net effect is that the electron will spiral along the direction of the fields, with its speed increasing due to the electric field while also being influenced by the magnetic field's perpendicular force. Ultimately, the electron's trajectory will be a helical path along the direction of the fields.
Two identical charged particles moving with same speed enter a region of uniform magnetic field If one of these enters normal to the field direction and the other enters along a direction at 30 with?
So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field. In the first case @ = 90 deg. As sin90 = 1 the force is Bqv. In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv. Hence the force on the latter will be half of that on the earlier one.
When are velocity and acceleration perpendicular to each other?
Velocity and acceleration are perpendicular to each other when the magnitude of the acceleration is equal to the centripetal acceleration required for circular motion, and the direction of the acceleration is towards the center of the circular path while the velocity is tangent to the path. This occurs in uniform circular motion.
A particle with a mass of 6.64 x 10-27 kg and a charge of plus 3.20 x 10-19 C is accelerated from rest through a potential difference of 2.45 x 106 V The particle then enters a uniform 1.60-T magnetic?
The kinetic energy gained by the particle due to the potential difference can be calculated using the formula KE = qV, where q is the charge and V is the potential difference. The kinetic energy can then be equated to the work done by the magnetic field, given by W = qvBd, where v is the velocity, B is the magnetic field, and d is the distance traveled in the magnetic field. Combining these equations can help determine the speed of the particle as it enters the magnetic field.
