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Two identical charged particles moving with same speed enter a region of uniform magnetic field If one of these enters normal to the field direction and the other enters along a direction at 30 with?
So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field. In the first case @ = 90 deg. As sin90 = 1 the force is Bqv. In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv. Hence the force on the latter will be half of that on the earlier one.
A particle with a mass of 6.64 x 10-27 kg and a charge of plus 3.20 x 10-19 C is accelerated from rest through a potential difference of 2.45 x 106 V The particle then enters a uniform 1.60-T magnetic?
The kinetic energy gained by the particle due to the potential difference can be calculated using the formula KE = qV, where q is the charge and V is the potential difference. The kinetic energy can then be equated to the work done by the magnetic field, given by W = qvBd, where v is the velocity, B is the magnetic field, and d is the distance traveled in the magnetic field. Combining these equations can help determine the speed of the particle as it enters the magnetic field.
How do you find distance with uniform velocity time final velocity and initial velocity?
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
What will be the force acting on the electron due to magnetic field of the solenoid when an electron is moving with a velocity V along the axis of a long straight solenoid carrying a current I?
When an electron moves along the axis of a long straight solenoid carrying a current I, the magnetic field inside the solenoid is uniform and directed along the axis. According to the Lorentz force law, the force acting on a charged particle moving in a magnetic field is given by ( F = q(\mathbf{V} \times \mathbf{B}) ), where ( \mathbf{V} ) is the velocity of the electron and ( \mathbf{B} ) is the magnetic field. Since the velocity of the electron is parallel to the magnetic field in the solenoid, the cross product ( \mathbf{V} \times \mathbf{B} ) equals zero. Thus, the force acting on the electron due to the magnetic field of the solenoid is zero.
If an object is moving at unifrom acceleration what is its velocity?
A body moving at a uniform speed may have a uniform velocity, or its velocity could be changing. How could that be? Let's look. The difference between speed and velocity is that velocity is speed with a direction vector associated with it. If a car is going from, say, Cheyenne, Wyoming to the Nebraska state line at a steady speed of 70 miles per hour, its velocity is 70 miles per hour east. Simple and easy. Uniform speed equals uniform velocity. (Yes, I-80 isn't perfectly straight there. Let's not split hairs.) But a car moving around a circular track at a uniform speed is constantly changing direction. Its speed is constant, but its velocity is changing every moment because the directionit is going is changing. Speed is uniform, but velocity isn't. As asked, uniform speed is a uniform distance per unit of time. And this will yield a uniform distance per unit of time in its velocity, but the direction vector may be uniform or it may be changing each moment, as illustrated.
What are examples of parabolas in physics?
A mass shot at an angle in a uniform gravitational field and a charged particle shot at an angle through a uniform electric field. The mass and the particle in their respective situations will both follow the path of a parabola (both will have a constant velocity perpendicular to the field and a constantly changing velocity parallel to the field).
When does a particle in motion have non-uniform velocity?
That simply means that its velocity is changing.
Why do electrons in a uniform magnetic field travel in a circular path?
It's because of how magnetic force is. The magnetic force is always perpendicular to both the magnetic field and the velocity of the electron, or any charged particle. If you draw x's on a piece of paper, representing the direction of the magnetic field into the paper, then draw a short vertical line up, representing the electron velocity, the magnetic force will be horizotal to the right. This causes the velocity to change direction a little toward the right. But now the force must change direction a little, etc., etc, until you get a circular path. BTW, you only get a circular path if the initial velocity is in the plane of the paper, perpendicular to the field. If the electron comes in at an angle from outside the paper the path will be a "screw" shape, circular and forward at the same time.
Which of the two an alpha particle or a proton projected normal to a uniform magnetic field would describe a path of smaller radius?
Assuming equal velocity. The alpha particle has twice the charge but four times the mass so it would have the wider radius.
How you find answers of aipmt2008?
a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be
Consider a particle moving with constant speed such that its acceleration of constant magnitude is always perpendicular to its velocity?
Centripetal force is a force that makes a body follow a curved path: it is always directed orthogonal to the velocity of the body, toward the instantaneous center of curvature of the path. - See more at: http://www.chacha.com/question/what-is-the-path-of-a-moving-body-whose-acceleration-is-constant-in-magnitude-at-all-times-and-is-perpendicular-to-the-velocity#sthash.pqrkWxfT.dpuf
Is it true or false that For a particle in uniform circular motion the instantaneous-acceleration vector is directed radially outward?
True. In uniform circular motion, the particle's velocity is tangential to the circular path, and the acceleration is directed radially inward, towards the center of the circular path. This centripetal acceleration causes the change in direction of the particle's velocity, but the magnitude of the velocity remains constant.
Two identical charged particles moving with same speed enter a region of uniform magnetic field If one of these enters normal to the field direction and the other enters along a direction at 30 with?
So the forces acting on these charges have to be compared. Is it so? The famous formula meant to know about the force acting on a moving charged particle entering into a magnetic field is given as F = B q v sin@ Here @ is the angle inclined by the moving particle with the magnetic field. In the first case @ = 90 deg. As sin90 = 1 the force is Bqv. In second case @ = 30 deg. As sin 30 = 1/2 the force is 1/2 Bqv. Hence the force on the latter will be half of that on the earlier one.
When are velocity and acceleration perpendicular to each other?
Velocity and acceleration are perpendicular to each other when the magnitude of the acceleration is equal to the centripetal acceleration required for circular motion, and the direction of the acceleration is towards the center of the circular path while the velocity is tangent to the path. This occurs in uniform circular motion.
What is the difference between uniform velocity and on uniform velocity?
I assume you mean "non-uniform". "Uniform" simply means that the velocity (in this case) doesn't change.
A particle with a mass of 6.64 x 10-27 kg and a charge of plus 3.20 x 10-19 C is accelerated from rest through a potential difference of 2.45 x 106 V The particle then enters a uniform 1.60-T magnetic?
The kinetic energy gained by the particle due to the potential difference can be calculated using the formula KE = qV, where q is the charge and V is the potential difference. The kinetic energy can then be equated to the work done by the magnetic field, given by W = qvBd, where v is the velocity, B is the magnetic field, and d is the distance traveled in the magnetic field. Combining these equations can help determine the speed of the particle as it enters the magnetic field.
When an object is moving with uniform circular motion the centripetal acceleration of the object?
The centripetal acceleration of an object in uniform circular motion is directed towards the center of the circular path and is perpendicular to the object's velocity. It is responsible for changing the direction of the object's velocity, keeping it moving in a circular path.
