paramagnetic; 2
The molecular orbital (MO) configuration for the diatomic molecule ( \text{B}2 ) is ( \sigma{1s}^2 , \sigma_{1s}^{}^2 , \sigma_{2s}^2 , \sigma_{2s}^{}^2 , \sigma_{2p_z}^2 , \pi_{2p_x}^1 , \pi_{2p_y}^1 ). In this configuration, the ( \sigma_{2p_z} ) orbital is filled before the ( \pi_{2p_x} ) and ( \pi_{2p_y} ) orbitals, reflecting the bond order of 1. Thus, ( \text{B}_2 ) has a total of two unpaired electrons, making it paramagnetic.
3/2 and paramagnetic
Another name for riboflavin is vitamin B2.
These codes typically refer to the levels of aflatoxin contamination found in a sample of food or feed. B1 and B2 are specific types of aflatoxins, while G1 and G2 are other types. M1 and M2 are metabolites of B1 and B2 that can be found in milk. High levels of these toxins can be harmful if consumed.
Riboflavin, also known as vitamin B2, is present in the body as coenzyme FAD and FMN. It is a component of various enzymes including amino acid oxidase, which is involved in the metabolism of amino acids.
B2 is paramagnetic due to the presence of unpaired electrons in its molecular orbital configuration. In B2, the molecular orbitals are filled as follows: σ(1s)², σ(1s)², σ(2s)², σ(2s)², and then σ(2p)², π(2p)², leading to two unpaired electrons in the π(2p) orbitals. In contrast, C2 has all its electrons paired, resulting in a completely filled set of molecular orbitals: σ(1s)², σ(1s)², σ(2s)², σ(2s)², σ(2p)², and π(2p)². Thus, C2 is diamagnetic because it lacks unpaired electrons.
Bromine is paramagnetic. This is because the 4p subshell has a value of 4p5. 5 electrons in a p subshell (which has space for 6), means the last electron is unpaired. The unpaired electron gives it the property of paramagnetism. Alternatively, Selenium is diamagnetic, as it has the outer subshell 4p4, meaning no electrons are unpaired.
The expected bond order for diatomic B2 is 1, calculated by subtracting the number of antibonding electrons from the number of bonding electrons in the molecular orbital diagram.
The bond order for B2+ is 1.5. This is calculated by taking the difference between the number of bonding electrons and anti-bonding electrons, and dividing by 2. In the case of B2+, there are 3 bonding electrons (2 from each B atom and 1 from the + charge) and 2 anti-bonding electrons, resulting in a bond order of 1.5.
The bond order of B2-1 is 1. This is because it has 1 electron more than the neutral boron molecule B2, which increases the number of bonding electrons, resulting in a bond order of 1.
B2 is diamagnetic because it has all paired electrons, which results in no net magnetic moment.
To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05To multiply a number in B2 by a number in B3 and then get 5% of the total, the formula would be as follows:=B2*B3*5%If you want to increase that total by 5% of itself, then the formula would be:=B2*B3*1.05
(Vitamin) B2.
The US patent number is US 7198789 B2.
The answer depends on the context, but bi is a variable, not a number. It could be the ith of a set of variables b1, b2, ... .Or it could be the square root of -b2.Or it could be a vector of magnitude b in the idirection.
Yes, as long as either number is 0. a2 + b2 = (a+b)2 a2 + b2 = a2 + 2ab + b2 0 = 2ab
(-8 + b2) - (5 + b2) = -8 + b2 - 5 - b2 = -13