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To find the mass of 9.70 × 10²⁴ molecules of methanol (CH₃OH), first calculate the number of moles using Avogadro's number (6.022 × 10²³ molecules/mol). This gives approximately 16.13 moles of methanol. The molar mass of methanol is about 32.04 g/mol, so the total mass is 16.13 moles × 32.04 g/mol ≈ 516.6 grams.
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What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
What is the mass (in grams) of 9.52 1024 molecules of methanol (CH3OH)?
To find the mass of 9.52 × 10²⁴ molecules of methanol (CH₃OH), first calculate the number of moles using Avogadro's number (6.022 × 10²³ molecules/mol). This gives approximately 15.8 moles of methanol. The molar mass of methanol is about 32.04 g/mol, so the mass is calculated by multiplying the number of moles by the molar mass, resulting in approximately 506 grams.
What is the mass in grams of 9.36 1024 molecules of methanol CH3OH?
To find the mass of 9.36 x 10²⁴ molecules of methanol (CH₃OH), we first need to determine the number of moles. Using Avogadro's number (6.022 x 10²³ molecules/mol), we calculate: [ \text{Moles of CH₃OH} = \frac{9.36 \times 10^{24} \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mol}} \approx 15.55 \text{ moles} ] The molar mass of methanol is approximately 32.04 g/mol. Therefore, the mass is: [ \text{Mass} = 15.55 \text{ moles} \times 32.04 \text{ g/mol} \approx 498.6 \text{ grams} ] Thus, the mass of 9.36 x 10²⁴ molecules of methanol is approximately 498.6 grams.
What is the mass in grams of 9.15 1024 molecules of methanol CH3OH?
To find the mass of 9.15 × 10²⁴ molecules of methanol (CH₃OH), we first need to determine the molar mass of methanol, which is approximately 32.04 g/mol. Using Avogadro's number (6.022 × 10²³ molecules/mol), we can convert the number of molecules to moles: ( n = \frac{9.15 \times 10^{24}}{6.022 \times 10^{23}} \approx 15.19 ) moles. Finally, we calculate the mass: ( \text{mass} = n \times \text{molar mass} = 15.19 , \text{mol} \times 32.04 , \text{g/mol} \approx 486.4 , \text{g} ).
What is the mass in grams of 9.71 x 1024 molecules of methanol?
To find the mass of 9.71 x 10²⁴ molecules of methanol (CH₃OH), we first need to determine the molar mass of methanol, which is approximately 32.04 g/mol. Next, we use Avogadro's number (6.022 x 10²³ molecules/mol) to convert molecules to moles: 9.71 x 10²⁴ molecules is about 16.14 moles. Finally, multiplying the number of moles by the molar mass gives: 16.14 moles x 32.04 g/mol ≈ 517.6 grams.
What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?
To calculate the mass of 9.32x10^24 molecules of methanol (CH3OH), you can first find the molar mass of CH3OH, which is approximately 32 g/mol. Then, you can convert the number of molecules to moles and finally to grams. The calculation would be (9.32x10^24 molecules) / (6.022x10^23 molecules/mol) * (32 g/mol) = 497 grams.
What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
To find the mass of 9.03 x 10^24 molecules of methanol (CH3OH), we first calculate the molar mass of CH3OH: (1 x 12.01 g/mol) + (4 x 1.01 g/mol) + (1 x 16.00 g/mol) = 32.04 g/mol Then we can convert the number of molecules to moles and finally to grams: 9.03 x 10^24 molecules * (1 mol / 6.022 x 10^23 molecules) * 32.04 g/mol ≈ 482 g
What is the mass in grams of 9.47 x 1024 molecules of methonal?
The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.
What is the mass of 3.62 X 1024 molecules of CH3OH?
To find the mass of 3.62 x 10^24 molecules of CH3OH, you need to first calculate the molar mass of CH3OH, which is 32.04 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the number of molecules to moles. Finally, multiply the number of moles by the molar mass to find the mass.
What is the mass in grams of 9.15 1024 molecules of methanol CH3OH?
To find the mass of 9.15 × 10²⁴ molecules of methanol (CH₃OH), we first need to determine the molar mass of methanol, which is approximately 32.04 g/mol. Using Avogadro's number (6.022 × 10²³ molecules/mol), we can convert the number of molecules to moles: ( n = \frac{9.15 \times 10^{24}}{6.022 \times 10^{23}} \approx 15.19 ) moles. Finally, we calculate the mass: ( \text{mass} = n \times \text{molar mass} = 15.19 , \text{mol} \times 32.04 , \text{g/mol} \approx 486.4 , \text{g} ).
How many grams are in a sample of sulphur trioxide that has 1.88 x 1024 molecules?
To calculate the grams of sulphur trioxide, first find the molar mass of SO3 (80.06 g/mol). Next, calculate the number of moles in 1.88 x 10^24 molecules. Then, multiply the number of moles by the molar mass to get the grams.
How many molecules are there in 200 grams of h2o?
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
How many molecules are there in 1x1024 molecules of BCl3?
1 x 1024 molecules
How many moles in 4.96 x 1024 molecules of glucose?
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
How many kilograms are in 1024 grams?
1.024
How many molecules would be found in 427.4 grams of potassium nitrate?
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
