The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.
The gram molecular mass of C6H12O6 is 180.16, Which can be found from summing 6 times the gram atomic mass of carbon, 12 times the gram atomic mass of hydrogen, and 6 times the gram atomic mass of oxygen. Therefore, by the definition and value of Avogadro's Number, the number of molecules of C6H12O6 in 720 grams of the substance is (720/180.16) X Avogadro's Number, or 2.41 X 1024 molecules, to the justified number of significant digits.
The relationship between number of moles and mass is: n = m/MW Where n is the number of moles, m is the mass in grams and MW is the molecular weight (or molecular mass). Subsituting the numbers into the equation: 2.5 mol = m/32 (from O2(g), 16 from each oxygen) m = 2.5 * 32 = 80 grams This also means that there is approximately 1.5 x 1024 molecules of O2 in your sample.
Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol The atomic mass of Fe is 55.8 Mass of Fe = 4.50 x 55.8 = 251g
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
The only difference is the name of the unit; the numerical values are the same. However, the value in amu is the mass of a single molecule, while the molecular weight in grams is the mass of Avogadro's number of molecules. The mass of Avogadro's number of molecules is called a Gram-mole. The molecular weight of , say, Hydrogen H2 is 2 amu. A gram mole of this would be 2 grams. The molecular weight in grams is the weight of this molecule in real grams and is an extremely small value.
192.678 grams CH3OH
A yottagram is a unit of mass equal to 1024 grams.
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
Mass of HCL given=3.46kgs = 3460 grams of HCL No. of moles of HCL=Mass of HCL provided/Atomic mass of HCL=3460/36.5=94.8 moles no. of molecules=no. of moles x Avogadro number=94.8 x 6.022 x 1023 =57 x 1024 molecules.
The gram molecular mass of C6H12O6 is 180.16, Which can be found from summing 6 times the gram atomic mass of carbon, 12 times the gram atomic mass of hydrogen, and 6 times the gram atomic mass of oxygen. Therefore, by the definition and value of Avogadro's Number, the number of molecules of C6H12O6 in 720 grams of the substance is (720/180.16) X Avogadro's Number, or 2.41 X 1024 molecules, to the justified number of significant digits.
To convert mass to atoms:Find the atomic mass of the element in the substance. You can find atomic masses on the periodic table. Ex. Lithium's atomic mass is 6.9 grams (round if you need to)Then find the mass of the substance in grams. Ex. you have 18.2 grams of a sample of Lithium.The mass of the sample is multiplied by 6.02 * 1023 and divided by the atomic mass.Ex.mass of sample in grams * (6.02 * 1023 atoms) / (atomic mass) = # atoms in grams18.2 grams * (6.02 * 1023 atoms) / (6.9 grams) = 1.59* 1024 atomsThe number 6.02 * 1023 is Avogadro's Constant which is the amount of atoms (or molecules) in one mole.
The mass is 49,06 g.
The mass is 483,62 g.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
The answer is 50,196 g.
The mass of ammonia is 339,7 g.