The relationship between number of moles and mass is: n = m/MW Where n is the number of moles, m is the mass in grams and MW is the molecular weight (or molecular mass). Subsituting the numbers into the equation: 2.5 mol = m/32 (from O2(g), 16 from each oxygen) m = 2.5 * 32 = 80 grams This also means that there is approximately 1.5 x 1024 molecules of O2 in your sample.
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
The number of grams in a mole of a molecule is found by looking at the atomic mass of each element on the periodic table. The molar mass of an element is it's atomic mass in grams. The atomic mass of oxygen is 15.999. Since there are two atoms of oxygen in a molecule of oxygen, the molar mass of oxgen (O2) is 15.999 x 2. That comes out to 31.998g/mol, or you can round to 32 if significant figures arn't important to you.
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
The mass of 0,2 moles of oxygen gas is 6,4 g.
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
28 mass of oxygen
The mass of one mole of oxygen atoms is listed on the periodic table (15.999g). Multiply this by three. Be careful. Oxygen is almost never found outside of a molecule. If you are looking for the mass of three moles of oxygen gas, that is three moles of O2. So, you will need to multiply the mass of the atom by two, then multiply by the number of moles.
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
The answer is 0,173 moles.
The answer is 0,8 moles oxygen.
6,5 moles oxygen equals 208 g.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
The equivalent in moles is 6,03.
The answer is 2 moles.