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The number of grams in a mole of a molecule is found by looking at the Atomic Mass of each element on the Periodic Table. The molar mass of an element is it's atomic mass in grams. The atomic mass of oxygen is 15.999. Since there are two atoms of oxygen in a molecule of oxygen, the molar mass of oxgen (O2) is 15.999 x 2. That comes out to 31.998g/mol, or you can round to 32 if significant figures arn't important to you.
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How many oxygen atoms are present in 40.0 grams of oxygen gas?
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
How many moles of oxygen are represent in 0.16 g of oxygen gas?
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
How many liters of oxygen gas are present in 11.3 grams of oxygen gas?
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
How many moles of oxygen in 30L of oxygen gas?
At standard temperature and pressure (STP), one mole of a gas is 22.4L. So, in order to determine how many moles of O2 are in 30L, you do the following: multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.
How many moles of oxygen gas are needed to react with 10.0 mol of ammonia?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
How many grams of O2 are in 50moles of the oxygen gas?
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g
How many moles are in 5.56g of oxygen gas (O2)?
The answer is 0,173 moles.
How many grams are in 6.5 moles of oxygen gas?
6,5 moles oxygen equals 208 g.
How many moles of oxygen gas are there in 135 liters of oxygen at Standard Temerature Pressure?
The equivalent in moles is 6,03.
How many oxygen atoms are present in 40.0 grams of oxygen gas?
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
How many moles of oxygen gas O2 are in 64 grams of O2?
The answer is 2 moles.
How many moles of potassium chlorate produce 6 moles of oxygen gas?
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
What is the mass of 0.2 moles of oxygen gas?
The mass of 0,2 moles of oxygen gas is 6,4 g.
How many moles of oxygen are represent in 0.16 g of oxygen gas?
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
How many moles of carbon dioxide are produced when 10.0 moles of propane are burned in excess oxygen on gas grill?
30 moles
How many no of moles are there in 16 gm of oxygen gas?
To find the number of moles in 16 g of oxygen gas, you need to divide the given mass by the molar mass of oxygen. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 16 g / 32 g/mol = 0.5 moles of oxygen gas.
How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?
Four moles of potassium chlorate are needed.
