Atomic weight of carbon: 12,011
Atomic weight of hydrogen: 1,008
Atomic weight of oxygen: 15,994
Molar mass of methanol: 12,011 + 15,994 + 4x1,008 = 32,037 g
The substance with a formula mass of 133.5 amu could be chloroform (CHCl3), which has a molar mass of 119.37 g/mol. The molar mass of any substance is equal to its formula mass in amu.
The molar mass of glucose is 180,16 g.
The molar mass of PbSO4 (lead(II) sulfate) is approximately 303.3 g/mol. This can be calculated by adding the molar masses of each element in the compound: lead (Pb) has a molar mass of 207.2 g/mol, sulfur (S) has a molar mass of 32.1 g/mol, and oxygen (O) has a molar mass of 16.0 g/mol.
The molar mass of H2Te = 129.61588 g/mol
Yes, the molar mass is different for isoelectronic molecules.
CHCl3 is a useful compound. molar mass of it is 119.5gmol-1.
The molar mass of chloroform (CHCl3) is 119.38 g/mol. The molar mass of chlorine in CHCl3 is 35.45 g/mol. To calculate the mass percent of chlorine, divide the molar mass of chlorine by the molar mass of chloroform and multiply by 100%. Therefore, the mass percent of chlorine in chloroform is 29.7%.
The molecular mass of CHCl3 is 119.37 g/mol. Chlorine has a molar mass of 35.45 g/mol. So the percentage by mass of chlorine in CHCl3 is (3 * 35.45) / 119.37 * 100 ≈ 89.0%.
To calculate the mass percent of chlorine in chloroform (CHCl3), you would first find the molar mass of the compound, which is 119.38 g/mol. Then, determine the molar mass of chlorine in the compound, which is 35.453 g/mol. Calculate the mass percent of chlorine by dividing the molar mass of chlorine by the molar mass of the compound and multiplying by 100. In this case, the mass percent of chlorine in chloroform is about 29.7%.
To find the molar mass of CHCl3, you would calculate the sum of the atomic masses of carbon, hydrogen, and three chlorine atoms. The atomic masses are: carbon (C) = 12.01 g/mol, hydrogen (H) = 1.01 g/mol, and chlorine (Cl) = 35.45 g/mol. Therefore, the molar mass of CHCl3 is 12.01 (C) + 1.01 (H) + 3*(35.45) (3 Cl) = 119.37 g/mol.
To calculate the percent composition by mass of chloroform (CHCl3), find the molar mass of each element (carbon, hydrogen, and chlorine) and the total molar mass of chloroform. Then, divide the molar mass of each element by the total molar mass and multiply by 100 to get the percentage of each element in chloroform.
From the Periodic Table the atomic masses are:- C = 12 H = 1 Cl = 35.5 Hence the molecular weight of CHCl3 = 12 + 1 + ( 3 x 35.5) = 119.5 Three masses of Cl = 3 x 35.5 = 106.5 Hence percentage mass of Cl in CHCl3 is 106.5 x 100 / 119.5 = 89.12%
To calculate the number of moles of chloroform in 198 g, you need to divide the mass of chloroform by its molar mass. The molar mass of CHCl3 is 119.38 g/mol, so 198 g ÷ 119.38 g/mol = 1.66 mol of chloroform.
The substance with a formula mass of 133.5 amu could be chloroform (CHCl3), which has a molar mass of 119.37 g/mol. The molar mass of any substance is equal to its formula mass in amu.
1.75 mole CHCl3 (6.02 X 10^23 mole CHCl3) = 1.05 X 1024 atoms of CHCl3 ====================
To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
molar mass of CHCl3 is119.5gmol-1. so there are 0.49 moles.