You need to have the weight per litre so you multiply by 4. 19.55x4 is 78.2 grams per litre. 78.2 divided by 58.443g/mol is 1.338 molar.
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
The molarity of the sugar solution can be calculated using the formula: molarity = moles of solute / liters of solution. Plugging in the values, molarity = 21.0 moles / 52.0 L which equals 0.404 Molarity.
The molarity is 0,1 M.
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
The molarity of the solution is 0.5 M.
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
A liter is equal to a dm3. So, we have 3,292 dm3 solution. We need the amount of the NaCl. It is m/M -> 17,62 / 58,5 -> approx. 0,3012 mol. So, the molarity is 0,3012 / 3,292 -> 0,0915 mol dm-3 .
It depends highly on the compound to be dissolved and the solvent. Molarity is measured my moles per litre, and if you don't know the molar mass of the compound, you can't work out the molarity.
In this case the molarity is 0,079 mol/L.
The molarity of the sugar solution can be calculated using the formula: molarity = moles of solute / liters of solution. Plugging in the values, molarity = 21.0 moles / 52.0 L which equals 0.404 Molarity.
concentration or molarity = number of moles/volume number of moles (n) = mass in grams of nacl/relative atomic mass of nacl n=17.52/(23+35.5) n = 0.2994872 mol volume = 2000/1000 = 2dm^3 molarity = 0.2994872/2 =0.15mol/dm^3
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.