Molarity is moles per litre. You need to multiply moles per 0.5 litres by 2. Doing this gives you 2.2 moles per litre, i.e. 2.2 molar.
This molarity is 1,59.
If 1,1 is grams the molarity is 0,317.
To find the mass of the solute (lithium sulfide) in 750mL of 0.188M solution, you need to multiply the volume of the solution (750mL) by the molarity (0.188 mol/L) and the molar mass of lithium sulfide (Li2S). First, calculate the number of moles in 750mL of 0.188M solution, then convert moles to grams using the molar mass of Li2S (45.88 g/mol).
- 37.1 kj/mol is the heat of solution for lithium chloride.
This is a lithium chloride water solution containing ions Cl- and Li+.
This molarity is 1,59.
If 1,1 is grams the molarity is 0,317.
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.
The molarity of the solution can be calculated by first finding the moles of lithium fluoride using its molar mass, which is 25.94 g/mol for lithium and 19.00 g/mol for fluorine. Add these together to find the molar mass of lithium fluoride. Then, divide the mass of lithium fluoride by its molar mass to get the moles. Finally, divide the moles by the volume of the solution in liters to get the molarity.
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
The molarity of the solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, 5 moles of lithium fluoride in 200 mL (or 0.2 L) of water gives a molarity of 25 M.
Molarity = moles of solute/Liters of solution ( 250.0 ml = 0.250 liters ) Find moles. 61.7 grams LiCl (1 mole/42.391 grams) = 1.455 moles lithium chloride Molarity = 1.455 moles LiCl/0.250 liters = 5.82 M LiCl -------------------
To find the mass of the solute (lithium sulfide) in 750mL of 0.188M solution, you need to multiply the volume of the solution (750mL) by the molarity (0.188 mol/L) and the molar mass of lithium sulfide (Li2S). First, calculate the number of moles in 750mL of 0.188M solution, then convert moles to grams using the molar mass of Li2S (45.88 g/mol).
An Arrhenius base that contains aluminum is Al(H2O)5OH2+ This ion has the unwieldy name pentaaquadihydroxoaluminum. An Arrhenius base that contains lithium is LiF. This compound is known as lithium fluoride and is basic because F- is the conjugate base of the weak acid HF, and thus will form hydroxide ions in solution.
Colorless
Lithium hydroxide is the Arrhenius base that contains the lithium cation.
To calculate the grams of lithium bromide present in the solution, you would first determine the moles of lithium bromide using the formula: moles = Molarity x Volume (L). Once you have the moles, you can convert it to grams using the molar mass of lithium bromide (86.85 g/mol).