The Mr of Carbon monoxide (CO) is 28, since Ar of Carbon is 12 and Ar of Oxygen is 16. Then proportion by mass will be simple ratio of 12 to 16 giving 3:4
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
2:1
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
The mole ratio of water vapor (H₂O) to hydrogen gas (H₂) can be determined from the balanced chemical equation for the combustion of hydrogen: 2 H₂ + O₂ → 2 H₂O. From this equation, we see that 2 moles of H₂ produce 2 moles of H₂O, resulting in a mole ratio of 1:1. Thus, for every mole of hydrogen gas, one mole of water vapor is produced.
The mole ratio of C5H12 to H2 in the reaction is 1:8. This means that for every 1 mole of C5H12, 8 moles of H2 are consumed or produced in the reaction.
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
The mole ratio of carbon (C) to oxygen (O) depends on the specific compound or reaction you are considering. For example, in carbon dioxide (CO₂), the mole ratio of C to O is 1:2, while in carbon monoxide (CO), it is 1:1. To determine the mole ratio, you must analyze the chemical formula or the reaction in question.
The mole ratio for the given equation is 1:2:1. This means that for every 1 mole of zinc (Zn) used, 2 moles of hydrochloric acid (HCl) are required to produce 1 mole of zinc chloride (ZnCl2) and 1 mole of hydrogen gas (H2).
2:1
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
1:3 because...in the equation N2+3H2---> 2NH3the product is 2NH3... there are 2 Nitrogens and 6 Hydrogens (2*3) making the ratio 2:6; but the correct simplified answer is 1:3
CO2 + H2 <-> CO + H2O all one to one ( I assume that 99.1 is grams. Always units!!!! ) 99.1 grams H2O (1 mole H2O/18.016 grams)(1 mole H2/1 mole H2O) = 5.50 moles of hydrogen gas needed If that was 99.1 moles water vapor then it would take 99.1 moles hydrogen gas at a one to one ratio.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
The mole ratio of water vapor (H₂O) to hydrogen gas (H₂) can be determined from the balanced chemical equation for the combustion of hydrogen: 2 H₂ + O₂ → 2 H₂O. From this equation, we see that 2 moles of H₂ produce 2 moles of H₂O, resulting in a mole ratio of 1:1. Thus, for every mole of hydrogen gas, one mole of water vapor is produced.
37.66 (g H2) / 2.016 (g/mol H2)= 18.68 mole H2Molar mass of hydrogen: 2.016 (g/mol H2)