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The mole ratio of water vapor (H₂O) to hydrogen gas (H₂) can be determined from the balanced chemical equation for the combustion of hydrogen: 2 H₂ + O₂ → 2 H₂O. From this equation, we see that 2 moles of H₂ produce 2 moles of H₂O, resulting in a mole ratio of 1:1. Thus, for every mole of hydrogen gas, one mole of water vapor is produced.
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How many grams of water form when 1.24L of H2 gas at STP reacts with O2?
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
How many moles of H2 are required to react with 5.0 moles O 2?
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
When h2 and o2 react water vapor is produced what type of reaction is this?
decomposition
What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
What is the mole ratio of C5H12 to H2 in the following reaction?
The mole ratio of C5H12 to H2 in the reaction is 1:8. This means that for every 1 mole of C5H12, 8 moles of H2 are consumed or produced in the reaction.
How many grams of water form when 1.24L of H2 gas at STP reacts with O2?
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 19.1 moles of water vapor?
CO2 + H2 <-> CO + H2O all one to one ( I assume that 99.1 is grams. Always units!!!! ) 99.1 grams H2O (1 mole H2O/18.016 grams)(1 mole H2/1 mole H2O) = 5.50 moles of hydrogen gas needed If that was 99.1 moles water vapor then it would take 99.1 moles hydrogen gas at a one to one ratio.
Give the mole ratio for the following equation Zn 2HCl -- ZnCl2 H2?
The mole ratio for the given equation is 1:2:1. This means that for every 1 mole of zinc (Zn) used, 2 moles of hydrochloric acid (HCl) are required to produce 1 mole of zinc chloride (ZnCl2) and 1 mole of hydrogen gas (H2).
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
What is the mole to mole ratio of nitrogen gas and hydrogen gas?
1:3 because...in the equation N2+3H2---> 2NH3the product is 2NH3... there are 2 Nitrogens and 6 Hydrogens (2*3) making the ratio 2:6; but the correct simplified answer is 1:3
How many moles of H2 are required to react with 5.0 moles O 2?
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
When h2 and o2 react water vapor is produced what type of reaction is this?
decomposition
What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted?
The balanced chemical equation for the reaction between sodium and water is: 2Na + 2H2O -> 2NaOH + H2 This means that for every mole of sodium (Na) reacted, one mole of hydrogen gas (H2) is produced. Therefore, when 0.066 mole of sodium is reacted, 0.066 mole of hydrogen gas will be produced.
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
How much water is made using 2kg hydrogen and 16kg of oxygen?
This equation and finding the limiting reactant.2H2 + O2 -> 2H2O2 kg H2 (1000 g H/1 kg H)(1 mole H/2.016 grams)= 992 moles hydrogen16 kg O2 (1000 g/1 kg)(1 mole O2/32.0 grams)= 500 moles oxygenI suspect hydrogen limits. Let's see.992 mole H2 (1 mole O2/2 mole H2)= 496 moles O2You have just a bit more than this in oxygen, so enough and hydrogen limits. ( check by going the other way and see the hydrogen limits )So, hydrogen drives the reaction.2 kg H2 (1000 g/1 kg)(1 mole H2/ 2.016 g)(2 mole H2O/2 mole H2)(18.016 g/1 mole H2O)(1 kg/1000 g)= 17.87 kilograms water made=========================( you do the significant figures )
