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c12h24
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What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 gmol?
To determine the molecular formula from the empirical formula CFBrO, we first calculate the molar mass of the empirical formula: C (12.01 g/mol) + F (19.00 g/mol) + Br (79.90 g/mol) + O (16.00 g/mol) = 126.91 g/mol. Next, we divide the given molar mass (381.01 g/mol) by the empirical formula mass (126.91 g/mol) to find the ratio: 381.01 g/mol ÷ 126.91 g/mol ≈ 3. The molecular formula is thus (CFBrO)₃, or C₃F₃Br₃O₃.
What is equal to carbons atomic mass and has the unit gmol?
Molar Mass
What is the percent of lead in lead IV oxide Or how do i calculate it?
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
What is the mass of 1 mol of rubidium?
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.
The molar mass of argon is 40 gmol. What is the molar mass of a gas if it effuses at 0.91 times the speed of argon gas?
graham's law (Rate 1 / rate 2) ^2 = MM2 / MM1 (Rate x / rate Ar) ^2 = MM Ar / MM x (.907)^2 = 39.9481 / MMx MMx = 39.9481 / 0.8226 Molar mass of unknown gas = 48.56 g / mole
What is the molecular formula of the compound ch2 with molar mass equals 168 gmol?
c12h24
What is the molecular formula of the compound CH2 with a molar mass 42.0 gmol?
The molecular formula of the compound is C2H4, which has a molar mass of 28 g/mol. Since the given compound has a molar mass of 42.0 g/mol, it must include an additional CH2 group, resulting in the molecular formula C2H6.
The empirical formula of a compound is ch2its molecular mass is 70 gmol what is its molecular formula?
C5h10
What is the molecular formula of a compound containing 89 cesium (Cs) and 11 oxygen (O) with a molar mass 298 gmol?
The molar mass of the compound is 298 g/mol. To find the molecular formula, we need to calculate the molar mass of Cs and O; Cs has a molar mass of approximately 132.91 g/mol, and O has a molar mass of approximately 16 g/mol. Using these values, we can determine that the compound's molecular formula is Cs11O11.
What is the molecular formula of the compound CH2 with molar mass 42.0 gmol?
c3h6
A compound with the empirical formula SN was found in a subsequent experiment to have a molar mass of 184.32 gmol. What is the molecular formula of the compound?
The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.
The analysis of an organic compound showed that it contains 0.175 mol C 0.140 mol H and 0.035 mol N. Its molecular mass is about 160 gmol. What is the subscript on C in the chemical formula?
The compound's empirical formula is CH3N, and its molecular formula is C4H12N. Therefore, the subscript on C in the chemical formula is 4.
What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 gmol?
To determine the molecular formula from the empirical formula CFBrO, we first calculate the molar mass of the empirical formula: C (12.01 g/mol) + F (19.00 g/mol) + Br (79.90 g/mol) + O (16.00 g/mol) = 126.91 g/mol. Next, we divide the given molar mass (381.01 g/mol) by the empirical formula mass (126.91 g/mol) to find the ratio: 381.01 g/mol ÷ 126.91 g/mol ≈ 3. The molecular formula is thus (CFBrO)₃, or C₃F₃Br₃O₃.
A compound formed of 0.059 mol hydrogen and 0.94 mol oxygen has a molecular mass of 34.0 g per mole. What is the molecular formula of this compound?
The molar ratio of hydrogen to oxygen in the compound is 2:1 based on the given number of moles. The molecular mass of the compound is 34.0 g/mol, which implies that the compound is H2O, water. The molecular formula of the compound is H2O.
What is the molecular formula of a compound containing 89 percent cesium Cs and 11 percent oxygen O with a molar mass equals 298 gmol?
The compound contains 1 cesium atom (Cs) and 1 oxygen atom (O). The molar mass of cesium is about 133.0 g/mol and oxygen is about 16.0 g/mol. Calculating the molar mass of Cs: (0.89 * 133.0 g/mol) = 118.37 g/mol Calculating the molar mass of O: (0.11 * 16.0 g/mol) = 1.76 g/mol Adding the molar masses together: 118.37 g/mol + 1.76 g/mol = 120.13 g/mol Thus, the molecular formula is CsO.
What does gmol-1 mean?
gmol-1 refers to grams per mole and is a unit of measurement commonly used in chemistry to express molar mass or molecular weight. It represents the mass of one mole of a substance in grams.
What does gmol -1 mean?
The notation "gmol⁻¹" refers to grams per mole, which is a unit of measurement used in chemistry to express the molar mass of a substance. It indicates how many grams of a substance are contained in one mole of that substance. For example, if a compound has a molar mass of 18 gmol⁻¹, it means that one mole of that compound weighs 18 grams. This unit is essential for converting between the mass of a substance and the amount of substance in moles.
