JohnDouggp7845
The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.
Wiki User
∙ 2014-11-06 14:03:17The empirical formula of this compound is CH2O.
The empirical formula for a compound whose molecular formula is P4O10 is P2O5 = phosphor pentoxide.
An empirical formula may or may not be the same as a molecular formula. The empirical formula of a compound shows the smallest whole-number ratio of the atoms compound. The molecular formula tells the actual number of each kind of atom present in a molecule of the compound.
Empirical formula: C3H2
This is the chemical formula (empirical formula) or the formula unit of this compound.
The empirical formula of this compound is CH2O.
The molecular formula is the same as the empirical formula, NO2. The compound NO2 has a molar mass of 46g/mol, so the empirical and molecular formulas are the same.
No: The molecular formula is never smaller than the empirical formula.
The empirical formula for a compound whose molecular formula is P4O10 is P2O5 = phosphor pentoxide.
Empirical Formula: CCl3
The formula of NO2 has a molecular weight of 46 g/mol. Your compound has a molecular weight of 92 g/mol. As you can see the molecular weight of the compound is twice that of the empirical formula. Therefore the molecular formula of your compound is:2 *(NO2) ---> N2O4
Yes, the empirical formula is the most basic ratio of the elements in a compound, while the molecular formula is the ratio in a compound. For instance C5H10O could be both the empirical and the molecular formula or the molecular formula could be C10H20O2 the molecular formula depends on the molar mass.
An empirical formula may or may not be the same as a molecular formula. The empirical formula of a compound shows the smallest whole-number ratio of the atoms compound. The molecular formula tells the actual number of each kind of atom present in a molecule of the compound.
CH2
c6h9o4=ch3o2
This is the chemical formula (empirical formula) or the formula unit of this compound.
If you know the molar mass of the compound, you have to calculate the mass of the empirical formula and divide the molar mass of the compound by the mass of the empirical formula in order to find the ratio between the molecular formula and the empirical formula. Then multiply all the atoms by this ratio to find the molecular formula!