H2O is polar because oxygen has a higher electronegativity
The molecular equation for the combustion of methane gas (CH4) in the presence of oxygen (O2) is: CH4 + 2O2 -> CO2 + 2H2O.
A molecule of CH4 (methane) is nonpolar due to its symmetrical tetrahedral shape, which allows the individual bond dipoles to cancel each other out. As a result, there is an even distribution of charge across the molecule, leading to no overall dipole moment. Consequently, CH4 does not exhibit significant polar characteristics.
if molecular shape is symmatrical then its non-polar but if it is non symmatrical then its polar.
Methane is an elementary organic compound having the molecular formula of CH4. Methane is composed of carbon (C) and hydrogen (H) atoms. The molecular weight of CH4 is 16. 01 grams per mole.
The polarity of a molecule is influenced by its molecular symmetry. Symmetric molecules tend to be nonpolar because any charges or dipoles within the molecule are canceled out by symmetry, while asymmetric molecules are more likely to be polar due to unbalanced distributions of charges or dipoles. Overall, molecular symmetry affects the overall polarity of a molecule.
The molecular formula of methane is CH4
CH4
CH4
The molecular equation for the combustion of methane gas (CH4) in the presence of oxygen (O2) is: CH4 + 2O2 -> CO2 + 2H2O.
Molecular geometry is tetrahedral has no lone pairs
The CH4 Bond Angle Will Be 109.5 Degrees Because It Has a Tetrahedral Molecular Geometry.
CH4 ia not polar.So the intra molecular force is london force
Fluorodiiodoborane
Methane's formula is CH4.
Molecular polarity is determined by the overall arrangement of polar bonds within a molecule. If a molecule has polar bonds that are arranged symmetrically, the molecule is nonpolar. However, if the polar bonds are arranged asymmetrically, the molecule is polar. Therefore, the relationship between molecular polarity and bond polarity is that the presence and arrangement of polar bonds within a molecule determine its overall polarity.
no
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant