60.04
The molecular weight of acetic acid (CH3CO2H) can be calculated from the component atomic weights of each of the atoms present in the molecule. In this particular example (C2H4O2) there are: 2 Carbon atoms with molecular weight of 12.01 = 24.02 4 Hydrogen atoms with molecular weight of 1.008 = 4.032 2 Oxygen atoms with molecular weight of 16.00 = 32.00 Therefore the total molecular weight of Acetic acid = 60.05 grams per mole
The formula weight of a molecule is determined by the elements that make up the molecule. For example, if you have H20, the weight of the molecule will be determined by multiplying the number of hydrogens (2) times the weight of the hydrogen element (1.008 grams) so this would equal 2.016 grams. Now the weight of one oxygen is 16 grams. Add the two together and you have your formula weight of the molecule equal to 18.016 grams. Basically, you break everything down into it's elemental form and determine the weights of each individual element and then multiply it by the number of each element in your molecule.
No, the reactants acetic acid (C2H4O2) and sodium bicarbonate (NaHCO3) react chemically to make other compounds (products): sodium acetate (NaC2H3O2) and carbonic acid (H2CO3), decomposing easily to carbon dioxide (CO2) and water (H2O)
The empirical formula is similar.
The carbohydrate molecule with the lowest molecular weight is formaldehyde (CH2O). It is the simplest form of carbohydrate, consisting of one carbon atom, two hydrogen atoms, and one oxygen atom.
In one molecule of C2H4O2, there are 4 atoms of hydrogen.
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
C2H4O2 represents the molecular formula for ethanoic acid, which is the compound acetic acid. Since this formula provides the actual number of each atom in a molecule, it is a molecular formula. To determine the empirical formula, you would need to simplify the ratio of the atoms present in the compound to the smallest whole number ratio, which in this case is CH2O.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
C2h4o2 is the molecular formula for CH2O.
C2H4O2 or CH3COOH
Vinegar is a solution, not a pure substance and thus does not have "a molecule". This solution is composed (in typical household vinegar) of 92% to 95% water and 5% to 8% acetic acid with small amounts of other chemicals that provide flavor or color. Perhaps you intended to ask about the number of atoms in a molecule of acetic acid. The formula of acetic acid is C2H4O2 this gives 8 atoms in a molecule.
Acetate is C2H4O2, not C6H5O2 !
Acetic acid: CH3COOH, or C2H4O2.
The elements in this compound are: carbon hydrogen oxygen
CH3- C(=O)OH Acetic acid is the archaic name for 'Ethanoic Acid'.
The molecular weight of citrate is approximately 192.13 g/mol.