No, the reactants acetic acid (C2H4O2) and sodium bicarbonate (NaHCO3) react chemically to make other compounds (products): sodium acetate (NaC2H3O2) and carbonic acid (H2CO3), decomposing easily to carbon dioxide (CO2) and water (H2O)
NaHCO3 is sodium bicarbonate (baking soda.) It is water soluble, and in solution it will dissociate into Na+ ions and HCO3- ions.
60.04
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 is commonly called bicarbonate of soda or baking soda.
Physical
No, the reactants acetic acid (C2H4O2) and sodium bicarbonate (NaHCO3) react chemically to make other compounds (products): sodium acetate (NaC2H3O2) and carbonic acid (H2CO3), decomposing easily to carbon dioxide (CO2) and water (H2O)
No, mixing C2H4O2 and NaHCO2 is not a physical change as it does not alter the chemical composition of the substances involved. It would simply be a physical mixing or dissolution of the two compounds.
In one molecule of C2H4O2, there are 4 atoms of hydrogen.
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
It is a chemical change. CH3COOH (vinegar) + NaHCO3 (baking soda) -> CH3COONA (sodium acetate) + H2CO3 (carbonic acid)...which then immediately dissociates to... H2CO3 -> H2O + CO2
NaHCO3 is sodium bicarbonate (baking soda.) It is water soluble, and in solution it will dissociate into Na+ ions and HCO3- ions.
As an overview, acetic acid (HC2H3O2 (or C2H4O2 in solution), from the vinegar) reacts with aqueous sodium bicarbonate (NaHCO3), forming sodium acetate (NaC2H3O2) and carbonic acid (H2CO3). As also happens in carbonated water, the carbonic acid then dissociates into water and carbon dioxide (H2O and CO2). The chemical reaction would be (not balanced): C2H4O2 + NaHCO3 --initial reaction--> NaC2H3O2 + H2CO3 --bubbling--> NaC2H3O2 + H2O + CO2
60.04
The answer is NaHCO3
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
The ratio of NaHCO3 to WHAT!
Crumple is a physical change.