The barycenter.
At the surface, it's about the same as the Earth's . You get a bit of variation in the value given, but, at the equator, it's about 1.065 times the Earth's. It is about 0.92 times the Earth's gravity, if you take into account the effect of the planet's rotation.
Gravity is a force created by and felt by mass. All massive objects have a force of gravity that is directly proportional to the amount of mass within the object. The gravitational constant is a coefficient that relates exactly how much mass = how much gravity. Given that the moon is less massive than the Earth, we would expect less gravity. Similarly, Jupiter has much more mass than the Earth and also has more gravity.
You will find a variation in the answers given for this even by reliable sources. The "surface" gravity of Saturn is certainly similar to Earth's. The value I normally use is: about 1.06 times Earth's surface gravity.
The gravity present on a planet is usually denoted by the acceleration an object would experience due to gravity on that planet's surface. If we stick to Newtonian gravity (which should be adequate for our present purpose) the acceleration due to gravity on a planet is given by: a = G*M / R^2 Where G is Newton's gravitational constant, M is the mass of the planet, and R is its radius (remember we are standing on the surface). (Note: Here I have neglected the vector qualities of acceleration, this will not matter at present, the acceleration will be pointing down, towards the center of the planet.) From this formula we can see that the acceleration increases if the mass of the planet increases. This is to be expected; gravity (in Newtonian gravity) is caused by mass, and thus a bigger mass means a stronger gravitational field. Since Venus is less massive than Earth we might expect the surface gravity on Venus to be less than on Earth. However, we also have the R^2 in the denominator. This means the surface gravity on a planet will increase if the radius decreases (and the mass stays the same). This is also clear; if the radius is less then you stand deeper into the gravitational field. Venus is about the same size as Earth so this effect should not play as much a role as the difference in mass does. Thus, just by using these arguments we can already conclude that the surface gravity on Earth is larger than the surface gravity on Venus. Let us now look at some numbers. Earth's surface gravity is about 9.81 m/s^2 (it varies slightly from location to location). And Venus' surface gravity is 8.87 m/s^2, which is less, as expected. This means that if you weigh 70 kg on Earth you will weigh 70*(8.87/9.81) = ~63 kg on Venus.
The strength of gravity from a given object is directly proportional to the object's mass and inversely proportional to the square of the distance from the center of mass. So, if we double an object's mass the gravity is double. If we triple the mass the gravity is tripled. By contrast if we double the distance we end up with one quarter the gravity. If we triple the distance we end up with only one ninth the gravity.The formula for the strength of gravity is: g=G*M/r^2"G" is the Newtonian gravitational constant, "M" is the mass of the object, and "r" is the distance tot he center of mass.In the case of the surface gravity of a planet, the distance to the center of mass is the planet's radius. So if two planets have the same mass but are of different sizes, the larger planet will actually have weaker surface gravity. In most cases a larger planet will have a greater mass than a smaller one, but not always as planets vary in density. Event if the larger planet is more massive, the larger size can still result in weaker gravity.A perfect example would be a comparison between Earth and Uranus. Uranus is about 4 times the radius and about 14.5 times the mass of Earth. From these figures we find that the gravity on Uranus is 0.906 times or 90.6% of Earth's surface gravity.
You can use plumb lines to find the center of gravity of an object.
A body can rotate about its center of gravity due to external forces, but not due to its own gravity. Use a free body diagram If no unbalanced forces exist, or a couple moment, then there will not be any forces to cause the body to rotate btw, the earth does not rotate because of its own gravity, the earth rotates because of the external forces given to the body of earth when the solar system formed. Don't quote me on it but this is my understanding I'm currently taking Statics and Dynamics in Engineering (Physics)
The force caused by the pull of gravity is called weight. Weight is the force with which an object is pulled towards the center of the Earth by gravity.
The force that acts downward is called gravity. It is the force that pulls objects toward the center of the Earth.
The time period of a simple pendulum at the center of the Earth would theoretically be zero because there is no gravitational force acting on it. A simple pendulum's period is determined by the acceleration due to gravity, which would be zero at the center of the Earth.
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
The pull of gravity on any given object is of course the objects weight. The acceleration an object undergoes while falling due to gravity's pull is approximately 9.8 m/s/s. (meters per second per second)
If gravity is the only force present, the total force acting on an object would be its weight, which is the force of gravity pulling it towards the center of mass of the larger body (like Earth). The weight is given by the formula: weight = mass x gravity.
Gravity is the force that pulls objects towards each other, given by the equation F = G(m1 * m2) / r^2. When loading a can, its weight and the force of gravity will be acting upon it, causing it to be pulled downwards towards the Earth's center.
Gravity is an attractive force that is exerted by all matter. Any two objects with mass will be attracted to one another. The greater the mass of the object, the stronger its gravity at any given distance. Most objects do not have enough mass for their gravity to be noticeable, but Earth does, as do all planets. Any object near Earth will be pulled in the direction of Earth's center.
Earth-Moon GravityThe point at which the gravity of the Earth is counterbalanced by the gravity of the Moon is much closer to the Moon. The stronger gravity of Earth has a greater effect for any given distance.Independent GravityThe Earth's gravity is greater than the Moon's, so the Moon would have a lower escape velocity and a lower possible orbit, even neglecting the fact that it has no atmosphere. Gravity diminishes with distance, so the effective gravity at any given distance from the Moon will be much less than the effective gravity at that distance from the Earth.
The ball will NOT come to rest. It will oscillate around the center of the earth in simple harmonic motion. Incorrect. the ball will rapidly reach a terminal velocity ( maximum speed given the resistance of the air). as the ball gets closer to the center of the earth it will slow down as the force pulling the ball towards the earth it has already passed through becomes closer to the force of the earth the ball has not yet passed. Upon reaching the center of the earth. the bal will minimal , and for a short time, oscillate until rapidly coming to rest at the center of gravity.