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What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
What is the time period of simple pendulum at the center of the earth?
The time period of a simple pendulum at the center of the Earth would be almost zero. This is because there is no gravitational force acting at the center of the Earth due to a balanced pull in all directions. Thus, the pendulum would not experience any acceleration and would not oscillate.
Can you conduct simple pendulum experiment at the centre of the earth?
It would not be possible to conduct a simple pendulum experiment at the center of the Earth due to extreme heat and pressure conditions. Additionally, the gravitational force at the center of the Earth would be effectively zero, which is essential for the functioning of a simple pendulum.
How the motion of simple pendulum is affected if it is placed at the center of earth?
If a simple pendulum is placed at the center of the Earth, it will experience zero net gravitational force because it is equidistant from all directions. As a result, the pendulum's motion would be unaffected and it would not swing back and forth due to the absence of a gravitational pull.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
What is the time period of simple pendulum at the center of the earth?
The time period of a simple pendulum at the center of the Earth would be almost zero. This is because there is no gravitational force acting at the center of the Earth due to a balanced pull in all directions. Thus, the pendulum would not experience any acceleration and would not oscillate.
What will be time period of simple pendulum at the centre of the earth?
at the center of the earth, simple pendulmn has not any gravitational force(if we thought,the earth is an etended object) so at the center the gravitational acceleation is about 'zero' and that's why pendulumn's time period is 'infinite'.
Can you conduct simple pendulum experiment at the centre of the earth?
It would not be possible to conduct a simple pendulum experiment at the center of the Earth due to extreme heat and pressure conditions. Additionally, the gravitational force at the center of the Earth would be effectively zero, which is essential for the functioning of a simple pendulum.
How the motion of simple pendulum is affected if it is placed at the center of earth?
If a simple pendulum is placed at the center of the Earth, it will experience zero net gravitational force because it is equidistant from all directions. As a result, the pendulum's motion would be unaffected and it would not swing back and forth due to the absence of a gravitational pull.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
How does altitude from the surface of earth affect the period of a simple pendulum?
The period of a simple pendulum is not affected by altitude from the surface of the Earth, as it is determined by the length of the pendulum and acceleration due to gravity, both of which are constant at different altitudes within reasonable ranges.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
What is the period of a simple pendulum 45 cm long on the Earth?
For small amplitudes, the period can be calculated as 2 x pi x square root of (L / g). Convert the length to meters, and use 9.8 for gravity. The answer will be in seconds. About 1.4 seconds.
What is the period of a simple pendulum 80 cm long a on earth and b when it is in a freely falling elevator?
a) The period of a simple pendulum on Earth depends on the acceleration due to gravity, which is approximately 9.81 m/s^2. Using the formula for the period of a pendulum, T = 2pisqrt(L/g), where L is the length of the pendulum (80 cm = 0.8 m), we find T = 2pisqrt(0.8/9.81) ≈ 1.79 seconds. b) In a freely falling elevator, the acceleration due to gravity acts on both the elevator and the pendulum, so the period of the pendulum remains the same as on Earth, assuming no air resistance or other external factors.
