The formula Sb(ClO₃)₅ refers to antimony pentachlorate. In this compound, antimony (Sb) is combined with five chlorate ions (ClO₃⁻). It is important in various chemical applications, particularly in the study of antimony's behavior in different chemical environments.
Sb Antimony
Group 15 elements (N, P, As, Sb, Bi)
To balance the equation Sb + O2 -> Sb2O3, you need to have 4 molecules of antimony (Sb) and 3 molecules of oxygen (O2) on each side of the equation. This gives you 2 antimony atoms combining with 3 oxygen molecules to form 2 molecules of antimony oxide.
The molecular name for PO5 is actually not valid, as it suggests an element named "po" combined with oxygen. If you meant phosphate with a charge of +5, then the correct formula would be PO4^5-.
It's in the metalloid group. Antimony (Sb) is a chemical element, a metalloid placed in the group 15 and period 5 of the periodic table of Mendeleev.
It isn't actually the 'molecular' formula because it is not molecule you ask about, but here is the formula of the chlorate anion:ClO3- in which the oxidation state of Cl is +5 and of O it is -2 (as ever in oxy-compounds). (The acid of this base is HCLO3, name: hydrogen chlorate, or better known as chloric acid).
Molecular formula: Al2Cl(OH)5 {or, more generally, Aln(OH)mCl3n-m }
Chlorite ( ClO2- ) is the base anion of chlorous acid: HClO2, the Oxidation number (or state) of Cl in this compoud is +3 according to this:oxidation state−1+1+3+5+7anion namedchloridehypochloritechloritechlorateperchlorateformulaCl-ClO−ClO2−ClO3−ClO4−
The oxidation number for Cl in ClO3 is +5 because the oxygen is assigned a value of -2, and there are 3 oxygen atoms in the ClO3 molecule. Since the molecule is neutral, the oxidation number for Cl must be +5 to balance out the charges.
The oxidation number of chlorine in ClO3 is +5. This is because oxygen typically has an oxidation number of -2, and there are three oxygen atoms in ClO3, totaling -6 overall. To balance the charge of the compound as a whole (which is neutral), the chlorine atom must have an oxidation number of +5.
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The oxidation number for Cl in ClO3 is +5. This is because oxygen has an oxidation number of -2 and there are 3 oxygen atoms in ClO3, resulting in a total oxidation number of -6. The overall charge of the ion is -1, so the oxidation number of Cl must be +5 to balance the charges.
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The sum of oxidation numbers in a compound is zero. In Sb2O5, oxygen typically has an oxidation number of -2. By setting up the equation: 2x + 5(-2) = 0, solving for x gives the oxidation number of Sb as +5.
In Sb₂O₄, oxygen is almost always assigned an oxidation number of -2. To find the oxidation number of Sb, you can set up the equation: 2x + 4(-2) = 0, where x is the oxidation number of Sb. By solving this equation, you'll find that the oxidation number of Sb in Sb₂O₄ is +5.