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The neutron-proton ratio for the nucleus of lead-206 ((^{206}_{82}\text{Pb})) can be calculated by determining the number of neutrons and protons. Lead-206 has 82 protons (as indicated by the atomic number) and 124 neutrons (calculated as 206 - 82). Thus, the neutron-proton ratio is 124 neutrons to 82 protons, which simplifies to approximately 1.51.

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