A phosphorus atom has 5 valence electrons and needs to gain 3 more to achieve a total of 8 valence electrons. By gaining 3 electrons, phosphorus becomes negatively charged, resulting in a charge of -3. Therefore, the resulting ion is a phosphide ion (P³⁻).
The PF6⁻ ion consists of one phosphorus (P) atom and six fluorine (F) atoms. Phosphorus has 5 valence electrons, and each fluorine atom has 7 valence electrons, contributing a total of 42 electrons from the six fluorine atoms. Adding the 5 from phosphorus and accounting for the extra electron due to the negative charge, the total number of valence electrons in PF6⁻ is 48.
Calcium has two valence electrons and needs to lose both to achieve a stable electron configuration, resulting in 8 valence electrons in the nearest noble gas configuration (argon). By losing these two electrons, calcium forms a cation with a charge of +2, resulting in a Ca²⁺ ion.
The formal charge of BH4 (tetrahydroborate) is 0. This is because boron (B) has 3 valence electrons and each hydrogen (H) contributes 1 valence electron, resulting in a total of 4 valence electrons for boron, which matches the number of valence electrons in a neutral boron atom.
It has a negative charge; to be more specific it has a charge of -3, since it has only 5 valence electrons and it would like to gain 3 more to be stable at 8.
The formal charge of SCO (sulfur monochloride oxide) is 0. This is because sulfur has 6 valence electrons, oxygen has 6, and chlorine has 7, totaling 19 valence electrons. When you draw the Lewis structure for SCO, each atom has the correct number of valence electrons, resulting in a formal charge of 0 for each atom.
A phosphorus ion (P3-) has 8 electrons in its outermost energy level. This is because phosphorus has 5 electrons in its outermost shell, and when it gains 3 electrons to become an ion, it will have 8 electrons in total in its outermost energy level.
Phosphate has a charge of -3 because it contains one phosphorus atom and four oxygen atoms, resulting in a total of five valence electrons. The phosphorus atom contributes three electrons, and each oxygen atom contributes one electron, making a total of eight electrons involved in bond formation.
The PF6⁻ ion consists of one phosphorus (P) atom and six fluorine (F) atoms. Phosphorus has 5 valence electrons, and each fluorine atom has 7 valence electrons, contributing a total of 42 electrons from the six fluorine atoms. Adding the 5 from phosphorus and accounting for the extra electron due to the negative charge, the total number of valence electrons in PF6⁻ is 48.
If magnesium (Mg) has a full valence shell, it would have a 2+ charge. This is because magnesium has 2 valence electrons and would need to lose these electrons to achieve a full valence shell, resulting in a 2+ charge.
The formal charge of P is 0 and the formal charge of F is 0.
The CN- ion has 10 valence electrons. The carbon atom contributes 4 valence electrons, and the nitrogen atom contributes 5 valence electrons. Additionally, the negative charge adds 1 electron, resulting in a total of 10 valence electrons.
Calcium has two valence electrons and needs to lose both to achieve a stable electron configuration, resulting in 8 valence electrons in the nearest noble gas configuration (argon). By losing these two electrons, calcium forms a cation with a charge of +2, resulting in a Ca²⁺ ion.
Sulfur, with its 6 valence electrons, will gain 2 electrons to achieve a stable octet configuration, resulting in a charge of -2.
The formal charge of BH4 (tetrahydroborate) is 0. This is because boron (B) has 3 valence electrons and each hydrogen (H) contributes 1 valence electron, resulting in a total of 4 valence electrons for boron, which matches the number of valence electrons in a neutral boron atom.
The valence electrons in nitrogen are located farther from the nucleus and shielded by inner electron shells, resulting in an increased screening effect and a higher effective nuclear charge experienced by the valence electrons. In contrast, the valence electrons in beryllium are in a lower energy level closer to the nucleus, which leads to a weaker screening effect and a lower effective nuclear charge.
For PBr4^+ you have...Valence electrons in P = 5Valence electrons is Br = 7 and there are 4 of them so total = 28This gives a total of 33, but you subtract 1 because of the + charge on the ion,Thus total valence electrons shown in the Lewis dot will be 32.
It has a negative charge; to be more specific it has a charge of -3, since it has only 5 valence electrons and it would like to gain 3 more to be stable at 8.