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At standard temperature and pressure (STP), 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, 1 mole of CO2 (carbon dioxide) would also occupy about 22.4 liters under these conditions. However, if the temperature and pressure differ from STP, the volume may vary accordingly.
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Calculate the gram atom in 22.4 liters of helium?
To calculate the number of gram atoms in 22.4 liters of helium, we first need to convert the volume to moles using the ideal gas law. Since helium is a monoatomic gas, 1 mole of helium is equivalent to 4 grams (its molar mass). Therefore, the number of gram atoms in 22.4 liters of helium would be 22.4 liters * (1 mole / 22.4 liters) * (4 grams / 1 mole) = 4 grams.
What is the ratio volume of volume occupied by 1 mole of o2 and 1 mole of o3?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, 1 mole of O₂ occupies 22.4 liters, and 1 mole of O₃ also occupies 22.4 liters, as it is also a gas under these conditions. Thus, the volume ratio of 1 mole of O₂ to 1 mole of O₃ is 1:1.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
who will have the greater number of ions 1 mole of nickel or 1 mole of copper?
The number is 6,022140857.10e23.
How can you calculate the number of liters of 2.30 mole of helium gas at STP?
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
How do you calculate the number of liters of 3.30 moles of helium at stp?
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
Calculate the gram atom in 22.4 liters of helium?
To calculate the number of gram atoms in 22.4 liters of helium, we first need to convert the volume to moles using the ideal gas law. Since helium is a monoatomic gas, 1 mole of helium is equivalent to 4 grams (its molar mass). Therefore, the number of gram atoms in 22.4 liters of helium would be 22.4 liters * (1 mole / 22.4 liters) * (4 grams / 1 mole) = 4 grams.
What is the ratio volume of volume occupied by 1 mole of o2 and 1 mole of o3?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, 1 mole of O₂ occupies 22.4 liters, and 1 mole of O₃ also occupies 22.4 liters, as it is also a gas under these conditions. Thus, the volume ratio of 1 mole of O₂ to 1 mole of O₃ is 1:1.
How many liters are within 3.5 mol of helium gas at STP?
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
What does avogadros law say about a gas at STP?
1 mole of gas at STP occupies 22.4 liters.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
How many liters of He gas would 1 mol of He occupy at STP?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 1 mole of helium (He) gas would occupy 22.4 liters at STP.
At stp how many moles of helium would occupy 1.00l?
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
How many liters are in 1.84 moles of helium?
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
What is the total number of carbon atoms contained in 22.4 liters of CO gas?
43.78 g PV=nRT n=(PV)/(RT) n=(1 ATM x 22.4 L)/(0.08206 x 273 K) n= 0.995 mol 0.995 mol CO2 x (44 g CO2/1 mol CO2)= 43.78 g CO2
