1 mole = 22.414 liters
So, 3.5 mole = 78.45 liters
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One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 1 mole of helium (He) gas would occupy 22.4 liters at STP.
The volume is 0.887 L.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
131.97 litres, of course!
The volume of 10.9 mol of helium at STP is 50 litres.