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8,4 liters of nitrous oxide at STP contain 2,65 moles.
One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
You divide the liters of gas by 22.4 to convert to moles. This is because one mole of gas at standard temperature and pressure (STP) occupies 22.4 liters.
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
The volume is 0.887 L.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP). Therefore, 68.5 liters of oxygen gas at STP would be 68.5/22.4 = 3.06 moles of oxygen gas.
One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.60 liters of Cl2 at STP would be: 5.60 L / 22.4 L/mol = 0.25 moles of Cl2.
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 15 liters of oxygen at STP would be equivalent to 15/22.4 = 0.67 moles.
You divide the liters of gas by 22.4 to convert to moles. This is because one mole of gas at standard temperature and pressure (STP) occupies 22.4 liters.