Question 5 of 15Ordering: Use the up and down arrows to order the list and then click "submit."
Each of the following molecules has a C-O bond. Rank these molecules in order of increasing C-O bond energy. Lowest Bond Energy
Highest Bond Energy
COCO2CO32-H3COH
The bond order of carbon monoxide (CO) is 3.
CO+ has a shorter bond length than CO- so its bond order is greater! As student yoyu are prbably expecte to use an MO diagram removing an electron from the HOMO highest occupied molecular orbital. there are different diagrams around. Some of them indicate that bond order will increase as you are removing an electron from an anti-bonding orbital a 2s-sigma. You may wish to look at the digram that your teacher has recommended and use that to get the "right" answer - the test is how to use MO diagrams after all.
The C-O bond order from smallest to largest would be: C-O single bond in methanol, C-O double bond in formaldehyde, and C-O triple bond in carbon monoxide.
CO is not a homo-nuclear atom like C2, N2 or even O3, O3 (both these categories are different: with and without 2s-2p mixing). So there is a large discrepancy in the atomic energy levels of 2s, 2p e- of C and O.As a result, 2p(pi)x, 2p(pi)y and 2p(sigma)z have lower energy than 2s(sigma)*. So the e- lost is from 2s(sigma)*2 and not 2p(sigma)z. And hence the bond order increases from 3 to 3.5 and not decreases to 2.5 . (The typical school textbook formula doesn't work for species like CO,CO+ and even NO,NO+ in many situations):-)
This type of bond exists in proteins, it is amide bond formed between nitrogen atom of one molecule and carbonyl carbon of 2nd molecule , as R-CO-NH-CH(R)-CO-
The bond order of carbon monoxide (CO) is 3.
The strength of the C-O bond generally follows this order: triple bond (CO) < double bond (CO2) < single bond (H3COH) < ionic bond (CO32-). Therefore, the order of increasing C-O bond length would be CO < CO2 < H3COH < CO32-.
Largest bond order: CO CO2 CO32- H3COH Lowest bond order apex answers
The bond order of carbon monoxide (CO) is 3. This is determined by subtracting the number of electrons in antibonding orbitals from the number of electrons in bonding orbitals and dividing by 2.
CO+ has a shorter bond length than CO- so its bond order is greater! As student yoyu are prbably expecte to use an MO diagram removing an electron from the HOMO highest occupied molecular orbital. there are different diagrams around. Some of them indicate that bond order will increase as you are removing an electron from an anti-bonding orbital a 2s-sigma. You may wish to look at the digram that your teacher has recommended and use that to get the "right" answer - the test is how to use MO diagrams after all.
The C-O bond order from smallest to largest would be: C-O single bond in methanol, C-O double bond in formaldehyde, and C-O triple bond in carbon monoxide.
CO is not a homo-nuclear atom like C2, N2 or even O3, O3 (both these categories are different: with and without 2s-2p mixing). So there is a large discrepancy in the atomic energy levels of 2s, 2p e- of C and O.As a result, 2p(pi)x, 2p(pi)y and 2p(sigma)z have lower energy than 2s(sigma)*. So the e- lost is from 2s(sigma)*2 and not 2p(sigma)z. And hence the bond order increases from 3 to 3.5 and not decreases to 2.5 . (The typical school textbook formula doesn't work for species like CO,CO+ and even NO,NO+ in many situations):-)
Despite having a stronger bond, carbon monoxide is more reactive than nitrogen due to the polar nature of the CO bond. The polarity allows for easier breaking and formation of bonds in CO compared to the nonpolar nitrogen molecule. This leads to higher reactivity in carbon monoxide even though it has a stronger bond.
Carbon monoxide (CO) has a triple bond between carbon and oxygen, indicating a strong covalent bond. This triple bond is composed of two(sigma) bonds and one(pi) bond.
No. A surety bond does not require one have a co-signer although depending on the purchasers credit score and financial background a co-signer could be necessary.
CO
This type of bond exists in proteins, it is amide bond formed between nitrogen atom of one molecule and carbonyl carbon of 2nd molecule , as R-CO-NH-CH(R)-CO-