Usually +2, but all the different charges (+3, +6) can be found in chromium's box on the table.
The oxidation state of chromium in dichromate ions (Cr2O7 2-) is +6. Each oxygen atom carries an oxidation state of -2, so with seven oxygen atoms in the ion, the total charge must be -2, which means each chromium atom carries an oxidation state of +6 to balance the charge.
The formula of chromium ion depends on its charge. For example, chromium in the +3 oxidation state forms the chromic ion (Cr3+), while chromium in the +6 oxidation state forms the chromate ion (CrO4^2-).
Chromium exhibits different colors in its common oxidation states. For example: Chromium(II) compounds are usually colorless. Chromium(III) compounds are typically green or violet. Chromium(VI) compounds are usually yellow or orange.
Hi, CrO5 is a compound which has the structure which has peroxide linkage(O2 2-) as shown: Thus the oxidation number of Chromium can be calculated as : Let the oxidation number of Cr be x, then x-2-2(2)=0 x-2-4=0 x-6=0 thus x=+6
The compound Cr(SO₃)₃ is called chromium(III) sulfite. It consists of chromium in the +3 oxidation state combined with three sulfite ions (SO₃²⁻). The Roman numeral III indicates the oxidation state of chromium in this compound.
The oxidation number of chromium in CrNO3 is +3. This is because the overall charge of the nitrate ion (NO3-) is -1, and there are 3 nitrate ions in Cr(NO3)3. Therefore, the oxidation number of chromium must be +3 to balance out the -3 charge from the nitrate ions.
The oxidation state of chromium in dichromate ions (Cr2O7 2-) is +6. Each oxygen atom carries an oxidation state of -2, so with seven oxygen atoms in the ion, the total charge must be -2, which means each chromium atom carries an oxidation state of +6 to balance the charge.
In CrO3, the oxidation number of chromium (Cr) is +6 and the oxidation number of oxygen (O) is -2. This is because oxygen typically has an oxidation number of -2, and there are three oxygen atoms in CrO3 to give a total charge of -6. To balance the charge, the chromium atom must have an oxidation number of +6.
The oxidation number of chromium in K2Cr2O7 is +6. Each potassium ion has an oxidation state of +1, and each oxygen atom has an oxidation state of -2. By setting up an equation based on the overall charge of the compound, it can be determined that chromium has an oxidation state of +6.
The oxidation state of chromium (Cr) in Ag2Cr2O7 is +6. This is because the total charge of the compound is zero, and the oxidation states of silver (Ag) and oxygen (O) are fixed. By assigning an oxidation state of +6 to oxygen, we can determine that chromium is in the +6 oxidation state.
The CrN cation is typically a chromium(III) cation, where chromium has a +3 oxidation state. This means that chromium has lost three electrons and has a charge of +3.
The oxidation number for chromium can vary depending on the compound it is part of. In general, chromium can have oxidation states ranging from -2 to +6.
The formula of chromium ion depends on its charge. For example, chromium in the +3 oxidation state forms the chromic ion (Cr3+), while chromium in the +6 oxidation state forms the chromate ion (CrO4^2-).
The correct formula for the ionic compound chromium chloride is CrCl3. This is because chromium (Cr) has a 3+ charge, and chloride (Cl) has a 1- charge, so three chloride ions are needed to balance the charge of one chromium ion.
The oxidation number of chromium (Cr) in dichromate ion (Cr2O7^2-) is +6. This is because oxygen (O) is typically assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two chromium atoms must have a total oxidation number of +12 to balance the charge.
The oxidation number of chromium (Cr) in CrO4^2- is +6. Since each oxygen atom has an oxidation number of -2, and the overall charge of the polyatomic ion is -2, the oxidation number of chromium can be determined by solving the equation: (oxidation number of Cr) + 4(-2) = -2.
The oxidation number of Cr in HCr2O7 is +6. This is because each oxygen atom has an oxidation number of -2, and there are four oxygen atoms in the dichromate ion (Cr2O7)^2-. The overall charge of the ion is -2, which means the two chromium atoms must have a total oxidation number of +12 to balance the charge, resulting in an individual oxidation number of +6 for each chromium atom.