Well, honey, the oxidation number of strontium in the hydride of strontium is +2. It's like asking if Betty White is a national treasure - the answer is obviously yes. So, in this case, strontium is happily rocking that +2 oxidation number like a boss.
strontium (which the atomic number is not 85 its 38) has 38 protons and 50 neutrons... hope this helps!
1+ is the normal oxidation number for hydrogen
In beryllium hydride (BeH2), the oxidation number of hydrogen (H) is -1. This is because beryllium (Be) typically has an oxidation state of +2, and to balance this, each hydrogen atom must have an oxidation state of -1, resulting in a neutral compound overall. Thus, in BeH2, each hydrogen contributes a total of -2, while beryllium contributes +2.
The atomic number for strontium chloride is determined by the element strontium, which has an atomic number of 38. Since chloride is an anion with a charge of -1, it does not affect the overall atomic number of the compound.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
In the compound hydrides such as lithium hydride (LiH) or sodium hydride (NaH), hydrogen has an oxidation number of -1.
strontium (which the atomic number is not 85 its 38) has 38 protons and 50 neutrons... hope this helps!
1+ is the normal oxidation number for hydrogen
Strontium has 2 valence electrons because it is in Group 2 of the periodic table. The oxidation number of strontium is typically +2, as it tends to lose those 2 valence electrons to achieve a stable electronic configuration.
2
Strontium is in the second group. It shows only +2 number.
Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium all have an oxidation state of plus 2.
The oxidation number of hydrogen in a compound other than a hydride is typically +1. This is because hydrogen usually forms covalent bonds where it shares an electron with another nonmetal, resulting in a slight positive charge on the hydrogen atom.
The oxidation number of Na in NaH is +1 because alkali metals like Na typically have a +1 oxidation state in compounds. The oxidation number of H in NaH is -1 because hydrogen usually has a -1 oxidation state when bonded to metals.
The oxidation number of oxygen in hydroxide (OH-) is -2 since oxygen typically has an oxidation number of -2 in compounds. The oxidation number of hydrogen in hydroxide is +1 since hydrogen usually has an oxidation number of +1 when bonded to nonmetals like oxygen.
In Sr(OH)2, strontium (Sr) has an oxidation number of +2 because it belongs to Group 2 of the periodic table. Oxygen (O) typically has an oxidation number of -2, so each hydroxide ion (OH-) has an oxidation number of -1.
Hydrogen can exhibit a negative oxidation state in compounds known as hydrides, where it gains an electron to become H-. Some examples include metal hydrides like sodium hydride (NaH) and covalent hydrides like borane (BH3).