The ferrous oxide is the oxdant.
Ag+
In the reaction between potassium permanganate (KMnO4) and hydrogen peroxide (H2O2), manganese in KMnO4 is reduced from +7 to +2 in the form of MnO2. The hydrogen peroxide is oxidized to water (H2O), where the oxygen in H2O2 goes from -1 to -2.
If Fe becomes Fe^2+ it has lost 2 electrons, and so the Fe has been OXIDIZED.
This is a single displacement reaction, specifically a redox reaction. In this reaction, iron displaces copper from copper sulfate to form iron sulfate and copper.
The ferrous oxide is the oxdant.
In this reaction, Ag^+ is the oxidizing agent. It undergoes reduction by accepting electrons from Fe to form silver metal, while Fe gets oxidized to Fe^3+ in the process.
AgNO3
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
Ag+
Iron (Fe) is the reducing agent in the reaction. It donates electrons to silver nitrate (AgNO3), causing the silver ions to gain electrons and form solid silver (Ag).
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
Fe
Any reaction occur.
Here are some redox reaction practice problems for you to work on: Balance the following redox reaction: Fe CuSO4 - FeSO4 Cu Identify the oxidizing agent and reducing agent in the reaction: 2K Cl2 - 2KCl Determine the oxidation state of sulfur in H2SO4 Balance the following redox reaction in acidic solution: MnO4- H2C2O4 - Mn2 CO2 Calculate the change in oxidation state for sulfur in the reaction: H2S Cl2 - S HCl Good luck with your practice!
The oxidation half-reaction for the given equation is: Fe → Fe2+ + 2e-. This represents the loss of electrons from iron (Fe) to form iron ions (Fe2+).
In the reaction between potassium permanganate (KMnO4) and hydrogen peroxide (H2O2), manganese in KMnO4 is reduced from +7 to +2 in the form of MnO2. The hydrogen peroxide is oxidized to water (H2O), where the oxygen in H2O2 goes from -1 to -2.