Ag+
Silver (Ag)
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
In the redox reaction between silver nitrate (AgNO3) and sodium (Na) to produce sodium nitrate (NaNO3) and silver (Ag), sodium is oxidized from 0 to +1 oxidation state, losing one electron, while silver is reduced from +1 to 0 oxidation state, gaining one electron. Therefore, a total of one electron is transferred in this reaction.
In the reaction between potassium iodide (KI) and silver nitrate (AgNO3), a precipitation reaction occurs, resulting in the formation of silver iodide (AgI), which appears as a solid precipitate, and potassium nitrate (KNO3) in aqueous solution. The balanced equation for the reaction is: 2KI(aq) + AgNO3(aq) → AgI(s) + KNO3(aq). This reaction is commonly used in laboratory settings to demonstrate the formation of insoluble salts.
The reaction is:LNaCl + AgNO3 = AgCl + NaNO3The white precipitate is silver chloride.
Ag- from Mav student D
Iron reduce silver cations.
AgNO3
Silver cations are reduced.
Ag+ (apex)
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
In the redox reaction, silver (Ag) has been reduced because it gains electrons in forming solid silver (Ag) from silver nitrate (AgNO3).
Sodium (Na) has been reduced.
Silver (Ag)
In this redox reaction, silver nitrate (AgNO3) is reacting with sodium (Na) to form sodium nitrate (NaNO3) and silver (Ag). The sodium is getting oxidized (losing electrons) while the silver in silver nitrate is getting reduced (gaining electrons).
In the redox reaction AgNO3 + NaNO3 + Ag, silver (Ag) is reduced from Ag+ to Ag with the gain of one electron. Therefore, one electron is transferred in this reaction.
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl Silver chloride is a white precipitate.