To determine the pH of a solution with a given concentration of hydrogen ions (H⁺), you can use the formula pH = -log[H⁺]. If "H plus x" refers to a specific concentration, you would replace "x" with that numerical value. For instance, if the concentration of H⁺ is 0.01 M, the pH would be 2, since pH = -log(0.01) = 2.
In a neutral solution, the H plus is equal to OH-. The pH level in such a solution is usually at 7.
To find the pH from the concentration of H₃O⁺ ions, use the formula pH = -log[H₃O⁺]. For a concentration of 6.22 x 10⁻³ M, the calculation is pH = -log(6.22 x 10⁻³) ≈ 2.21. Thus, the pH of the solution is approximately 2.21.
A pH of 0 corresponds to a H+ concentration of 1.0 x 10^-0 M, a pH of 7 corresponds to a H+ concentration of 1.0 x 10^-7 M (neutral), and a pH of 14 corresponds to a H+ concentration of 1.0 x 10^-14 M.
[H+] = 1 x 10-10 M then pH = 10
The concentration of H+ ions in a solution with pH 2.5 is 3.16 x 10^-3 moles per liter.
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
5.0 x 10-3 pH = - log [H3O+] [H3O+] = 1 x 10^-pH pH = 2.3 [H3O+] = 1 x 10^(-2.3) = 5 x 10^(-3) M
The pH of a solution with an H+ concentration of 7.0 x 10^-12 is 11.15. This is calculated by taking the negative logarithm (to base 10) of the H+ concentration.
apexvs answer 3.3
-log(9.40 X 10^-4) = 3 pH
The pH of a solution can be calculated using the formula pH = -log[H+]. Substituting the given value of [H+] = 7.0 x 10^-12 into the formula gives pH = -log(7.0 x 10^-12) ≈ 11.2. Therefore, the pH of the solution is approximately 11.2.
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
The pH of a solution with a H+ concentration of 7.0 x 10^-2 M can be calculated using the formula pH = -log[H+]. In this case, pH = -log(7.0 x 10^-2) = 1.15.
1.70
In a neutral solution, the H plus is equal to OH-. The pH level in such a solution is usually at 7.
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.