What is the pressure of 4 miles of helium in a 50 L tank at 308 K?

Answer 1

To determine the pressure of helium in a 50 L tank at 308 K, we can use the Ideal Gas Law, ( PV = nRT ). First, we need to calculate the number of moles of helium in 4 miles, which is approximately 4 moles (since 1 mile ≈ 1 mole for helium). Using the values ( n = 4 ) moles, ( R = 0.0821 , \text{L·atm/(K·mol)} ), and ( T = 308 , \text{K} ), we can rearrange the equation to solve for pressure ( P ):

[ P = \frac{nRT}{V} \approx \frac{4 \times 0.0821 \times 308}{50} \approx 3.21 , \text{atm}. ]

Thus, the pressure of the helium is approximately 3.21 atm.