2.02 atm (apex)
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
2.02 atm
The pressure is 2,02 atmospheres.
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
The pressure will be 2,02 atmospheres.
2.02 atm
The pressure is 2,02 atmospheres.
2.02 atm
Using the ideal gas law equation PV = nRT, we can rearrange it to solve for pressure (P). Substituting the values given: n = 4 moles, V = 50 L, T = 308 K, and R = 0.0821 L.atm/(mol.K), we can calculate the pressure of helium in the tank. P = (4 moles)(0.0821 L.atm/(mol.K))(308 K)/(50 L). Therefore, the pressure of 4 moles of helium in a 50 L tank at 308 K is approximately 2.5 atm.
2.02atm
Using the ideal gas law (PV = nRT), where P is pressure, V is volume, n is number of moles, R is the ideal gas constant, and T is temperature in Kelvin, we can solve for pressure. Plugging in the values, the pressure of the 4 moles of helium in a 50 liter tank at 308 K is approximately 81.6 atm.
To determine the pressure of helium in a 50 L tank at 308 K, we can use the Ideal Gas Law, ( PV = nRT ). First, we need to calculate the number of moles of helium in 4 miles, which is approximately 4 moles (since 1 mile ≈ 1 mole for helium). Using the values ( n = 4 ) moles, ( R = 0.0821 , \text{L·atm/(K·mol)} ), and ( T = 308 , \text{K} ), we can rearrange the equation to solve for pressure ( P ): [ P = \frac{nRT}{V} \approx \frac{4 \times 0.0821 \times 308}{50} \approx 3.21 , \text{atm}. ] Thus, the pressure of the helium is approximately 3.21 atm.
We can use the equation PV=nRT. There are 2.048#10^5 pascels.