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Assuming that each parent is a carrier for cystic fibrosis (has the genotype Ff), the probability that their second child will develop cystic fibrosis is one fourth.

The probability doesn't change with the number of children they have. For each pregnancy, the chance that the child will have cystic fibrosis (have the genotype ff) is exactly the same.

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15y ago

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What is a punnett square for cystic fibrosis?

A Punnett square for cystic fibrosis would involve crossing two parents who are carriers of the recessive allele for the disease (denoted as "cf"). The square would show the probability of having a child with cystic fibrosis (25%), a carrier (50%), or unaffected by the disease (25%). Each parent would have a genotype of "Cf" (carrier) for the Punnett square.


How do you prove if something is heterozygous?

The carrier must be Homozygous because if he were hetero it must be Hh and the dominant gene is expressed but homozygous gives them the possibility of hh (only a carrier) or HH (definitely a carrier) Don't totally understand the previous answer; however, I understand the question to mean that you want to know if you are homozygous or heterozygous for a certain trait. If you express a recessive phenotype, that is you have blue eyes for example, you are definitely homozygous for that trait. If one of your parents has a recessive trait, like blue eyes, and the other parent expresses a dominant trait, like brown eyes, AND if you have brown eyes, you can be sure that you are heterozygous. Otherwise it is impossible to tell until you have children. Then you can work backwards from you and your spouse, look at their parents and your parents and then figure the only possible way all those conditions could exist is if you are heterozygous or if you are homozygous for that trait.


What are the possible phenotypes of the offspring between a parent who is a heterozygous carrier for cystic fibrosis and a homozygous normal parent?

The chances are one half. You will most likley have 2 children without the gene, and 2 with one gene. Since the normal parent has the dominate allele, the Cystic Fiborisis will not be present.


Another plant is said to be heterozygous for flower color what does this mean?

homozygous means that the alleles that make up the genotype are the same, for example homozygous dominant would have two dominant alleles (RR) or homozygous recessive would have two recessive alleles (rr). the alternative would be heterozygous, where the genotype contains both a dominant and a recessive allele (Rr). so a homozygous plant would either have two dominant alleles or two recessive alleles for the seed colour. Now the way to find out whether it is homozygous dominant or homozygous recessive is to do a cross with a homozygous recessive plant and look at the seed colour (the phenotype). if the the original genotype is homozygous dominant the offspring seed colour will show the dominant seed colour becasue it will be heterozygous. But if the original plant is homozygous recessive the offspring will show the recessive phenotype.


What is a carrier of hereditary traits?

Most traits in our body are linked to two genes, one from our mother and one from a father. If you are a carrier for a genetic disease, it means that you have one defective gene and one "normal" gene.

Related Questions

Is cystic fibrosis dominant or recessive?

Cystic Fibrosis is recessive. If you have one CF gene and one non-CF gene, you will be a carrier but not have CF.


How do you deterime phenotypes?

phenotypes are decided by the alleles for that particular characteristic, by a dominant or two recessive alleles. For example, cystic fibrosis has a recessive allele so the phenotype of cystic fibrosis would only appear if there were two of the recessive allele, one from each parent, were present. A heterozygous carrier of the cystic fibrosis allele would show the phenotype of not having cystic fibrosis. So to determine the phenotype simply find out which allele is dominant and find what alleles each parent has the the probability of each phenotype can be calculated


An individual heterozygous for cystic fibrosis?

Is a carrier of cystic fibrosis


What is the probability of two healthy people where one is a carrier being parents to a child born with cystic fibrosis?

If only one person is a carrier of cystic fibrosis than there is no chance of having a child with it. Both parents have to be carriers and even then there is only a 25% chance. If only one carries than there is a 50% chance that their children will carry but will not have cystic fibrosis.


What is a punnett square for cystic fibrosis?

A Punnett square for cystic fibrosis would involve crossing two parents who are carriers of the recessive allele for the disease (denoted as "cf"). The square would show the probability of having a child with cystic fibrosis (25%), a carrier (50%), or unaffected by the disease (25%). Each parent would have a genotype of "Cf" (carrier) for the Punnett square.


Is it possible for a mother to have two kids with different father be born with cystic fibrosis?

Depends. If your mother has cystic fibrosis and your father is a carrier, there is a 50% chance that any of their children will have cystic fibrosis. If the father is not a carrier, no children will have cystic fibrosis, but they will all be carriers.


Two parents who were phenotypically normal had to children The oldest was also phenotypically normal but the younger child had cystic fibrosis what is happening in the cross?

Cystic fibrosis is an autosomal recessive genetic disorder, meaning that a child must inherit two copies of the mutated gene (one from each parent) to express the condition. In this scenario, both parents are likely carriers of the cystic fibrosis allele (genotype Cc), where "C" is the normal allele and "c" is the mutated allele. The older child is phenotypically normal, which could mean they are either homozygous dominant (CC) or a carrier (Cc), while the younger child inherited two copies of the mutated allele (cc) from both parents, resulting in cystic fibrosis. This cross illustrates Mendelian inheritance patterns, where two carrier parents can have a child with a recessive condition.


Is cystic fibrosis controlled by a dominant allele or by a recessive allele?

It is controlled by a recessive allele. The gene encodes a chloride ion channel that is required to make sweat, mucus and a few other things. One copy of the gene is sufficient to prevent cystic fibrosis, and it is only when both copies are defective that the person would have the disease and show symptoms.


What health problems would i have if i carried the cystic fibrosis gene?

A carrier is someone who has a gene, but does not express that gene. It's like someone holding a book but is not capable of reading it. The carrier has no symptoms of the disease. The carrier can have a child with cystic fibrosis if the other parent is also a carrier of that gene.


What is the genotype of an individual that is not affected with cystic fibrosis?

Let's call the gene "C." Capital C means no cystic fibrosis; lower c means cystic fibrosis, since it is a recessive gene. CC is a person who does not have cystic fibrosis and also is not a carrier. Cc indicated a carrier. cc shows a person with cystic fibrosis. In order for a child to have cystic fibrosis, its parents must be: 1. cc and cc (both have cystic fibrosis, so every child will as well.) 2. Cc and Cc (both carriers; 25% chance of having a child with cystic fibrosis) 3. Cc and cc (one parent is a carrier and one has cystic fibrosis; there is a 50% chance that the children will have cystic fibrosis.)


If a dominant homozygous reproduced with a heterozygous could their offspring be recessive?

Let's see what combinations can be formed.HH, HH, Hh, Hh.So, yes their offspring can contain the recessive allele.(THe offspring can be a carrier of the recessive allele.)However, since it is impossible for the offspring to be homozygous recessive,the recessive trait/gene will not show in the offspring's phenotype.Hope that helps!


What is the probability of a down syndrome carrier male and a non-carrier female producing non-carrier children?

50%