KBrO3 is a more effective bleaching agent than NaOCl. KBrO3 is a stronger oxidizing agent and can react with a wider range of compounds, making it more versatile for bleaching applications.
The reaction between KBrO3 (potassium bromate) and H2S (hydrogen sulfide) is a redox reaction that forms Br2 (bromine) and S (sulfur) as products. The balanced equation is 6KBrO3 + 3H2S → 5Br2 + 3S + 6H2O + 3KBr.
The oxidation of isopentyl mercaptan (C5H12S) with potassium bromate (KBrO3) typically involves the conversion of the thiol group (-SH) to a sulfonic acid group (-SO3H). A simplified equation for this reaction can be represented as: C5H12S + KBrO3 + H2SO4 → C5H11SO3H + KBr + H2O This equation shows the reactants and products involved in the oxidation process, although the specific conditions and stoichiometry may vary based on experimental details.
An Internal Structure is the way an organism looks on the outside and an External Structure is the looks on the outside.
it is a simple structure
KBrO3 is neutral because it does not donate or accept protons in water.
As it contains the alkali metal potassium and the halogen bromine it is likely to be ionic
KBrO3 is a more effective bleaching agent than NaOCl. KBrO3 is a stronger oxidizing agent and can react with a wider range of compounds, making it more versatile for bleaching applications.
KBrO3
It could be KHBr2O6 (in analogy with disulfate), though I'm not sure about its existance.
potassium bromide
The oxidation number of Br in KBrO3 is +5. This is because oxygen typically has an oxidation number of -2 and the overall compound has a neutral charge. Since there is only one Br atom in KBrO3 and the oxidation numbers of K and O are known, the oxidation number of Br can be calculated as +5 to balance the overall charge.
When MnO2 is mixed with KBrO3 and 9M sulfuric acid, a reaction may occur where MnO2 is reduced to Mn2+ while KBrO3 is reduced to Br− ions. The sulfuric acid serves as a catalyst for this reaction, promoting the redox reactions. The overall reaction may release oxygen gas as a byproduct.
Potassium bromate
The reaction between KBrO3 (potassium bromate) and H2S (hydrogen sulfide) is a redox reaction that forms Br2 (bromine) and S (sulfur) as products. The balanced equation is 6KBrO3 + 3H2S → 5Br2 + 3S + 6H2O + 3KBr.
KBrO3 and KBr do not react with each other because they have same cation K+, but separately they react with H2SO4. 2KBrO3 + H2SO4 -------> K2SO4 + 2HBrO3 2KBr + H2SO4 ----------> K2SO4 + 2HBr
When KBrO3is heated it decomposes into KBr and oxygen.The balanced equation is 2 KBrO3 -> 2 KBr + 3 O2.