Zero. First n=3; second l = 0; third m = 0.
Azimuthal quantum number
The principle quantum number of a hydrogen electron in its ground state is 1.
the quantum number n determines the energy of an electron in a hyrdogen atom.
In the electron configuration of aluminum, the 3p1 electron corresponds to the 3rd energy level (n=3) and is in the p subshell. The second quantum number, also known as the azimuthal quantum number (l), for a p subshell is 1. Therefore, the second quantum number of the 3p1 electron in aluminum is l = 1.
Quantum numbers are values used to describe various characteristics of an electron in an atom, such as its energy, angular momentum, orientation in space, and spin. These numbers are used to define the allowed energy levels and possible configurations of electrons in an atom.
n = 2
mi=0
ml=0
n=1
l=0
ml = 0
3
The second quantum number refers to the azimuthal quantum number, also known as the angular momentum quantum number. For an electron in the 1s orbital of phosphorus (1s2), the azimuthal quantum number is 0, which corresponds to an s orbital. Therefore, for a 1s2 electron in phosphorus, the second quantum number would be 0.
l=1
ml = -1
What is the atom of 1s22s22p63s23p3 Answer: Phosphorus.
The first quantum number of a 2s electron in phosphorus is the principal quantum number, which specifies the energy level of the electron shell. For a 2s electron, the principal quantum number is 2.