Zero. First n=3; second l = 0; third m = 0.
The third quantum number, known as the magnetic quantum number (m_l), describes the orientation of the orbital. For a 3s electron, the principal quantum number (n) is 3, and the azimuthal quantum number (l) for an s orbital is 0. Therefore, the magnetic quantum number for a 3s electron is m_l = 0.
Azimuthal quantum number
The third quantum number, known as the magnetic quantum number (m_l), describes the orientation of the orbital in which the electron resides. For the 2s orbital, which is spherical, the magnetic quantum number can only be 0. Therefore, for the 2s¹ electron in aluminum, the third quantum number (m_l) is 0.
The second quantum number, also known as the azimuthal quantum number (l), describes the shape of the electron's orbital. For a 3p electron, the value of l is 1, corresponding to the p subshell. Therefore, the second quantum number of the 3p1 electron in aluminum is 1.
The first quantum number, also known as the principal quantum number (n), indicates the energy level of an electron in an atom. For a 2s electron in phosphorus, which has an electron configuration of 1s² 2s² 2p⁶ 3s² 3p³, the principal quantum number is 2. This indicates that the electron is located in the second energy level.
n = 2
mi=0
ml=0
n=1
l=0
ml = 0
3
The second quantum number refers to the azimuthal quantum number, also known as the angular momentum quantum number. For an electron in the 1s orbital of phosphorus (1s2), the azimuthal quantum number is 0, which corresponds to an s orbital. Therefore, for a 1s2 electron in phosphorus, the second quantum number would be 0.
l=1
ml = -1
What is the atom of 1s22s22p63s23p3 Answer: Phosphorus.
The first quantum number of a 2s electron in phosphorus is the principal quantum number, which specifies the energy level of the electron shell. For a 2s electron, the principal quantum number is 2.