The voltage for a constant current (CC) power supply at 110 amps depends on the specific load and application. Generally, the voltage will vary based on the resistance of the load according to Ohm's Law (V = I × R). For example, if the load has a resistance of 5 ohms, the voltage would be 550 volts (110 A × 5 Ω). Always refer to the power supply specifications and the load characteristics to determine the exact voltage needed.
If you need 50 amps you can use a 60 amp generator or any other generator rated to supply more amps. The voltage, 110 v or 240 v, must be the right voltage for the load used.
Depends on the supply voltage. For UK 230 Volts, 1800 Watts would mean the current drawn was 7.83 Amps.Watts=Volts x Amps, so Watts divided by Volts gives the current in amps.
Find out your supply voltage, and divide 65 by it: I(amps) = P(watts)/V(volts) = 65/V
A watt is a unit of power, and power is given by P = IV where P is power, I is current and V is voltage. Therefore, P = IV = (7.8A)*(110V) = 858A*V = 858W
Using 110 volt service, 5,000/110= 45 amps
If you need 50 amps you can use a 60 amp generator or any other generator rated to supply more amps. The voltage, 110 v or 240 v, must be the right voltage for the load used.
The maximum current will depend on the voltage of the power supply. For a supply at 240 volts, the max current will be 15000/240 = 62.5 amps. For a supply at 110 volts, the max current will be 15000/110 = 136.36amps to two significant figures.
Depends on the supply voltage. For UK 230 Volts, 1800 Watts would mean the current drawn was 7.83 Amps.Watts=Volts x Amps, so Watts divided by Volts gives the current in amps.
Find out your supply voltage, and divide 65 by it: I(amps) = P(watts)/V(volts) = 65/V
A watt is a unit of power, and power is given by P = IV where P is power, I is current and V is voltage. Therefore, P = IV = (7.8A)*(110V) = 858A*V = 858W
Using 110 volt service, 5,000/110= 45 amps
To operate this type of low voltage wrench, a power supply will have to be used. When looking for this type of power supply the output has to be 12 volts DC with a capacity of 15 amps or W = A x V = 180 watts.
A typical microwave rated at 1100 watts uses 10 amps of power. This is calculated by dividing the number of watts by the voltage of 110.
The formula you are looking for is W = A x V.
Power = volts times amps, so an appliance drawing 10 amps at a line voltage of 110 volts is consuming 1,100 watts. Keep in mind, however, that in a non purely resistive load, the phase angle of amps to volts might not be zero degrees, so the calculation becomes more complex, and depends on power factor, or phase angle.
power equals current times voltage 50w=(I)110v so 50w\110v = I .454 amps
The input power of a computer Power Supply is usually 110-240VAC. The power supply usually transforms the input voltage into 3.3V, 5V, and 12V...all in DC. Different components require different voltage...either (1)ONE of a combination of these. 12V is one output voltage of the PSU(Power Supply)