0
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
What else can I help you with?
What is the overall voltage for a redox reaction with the half-reactions Mg(s) Mg2 2e- and Cu2 2e- Cu(s)?
0.34-(-2.37)
How do you calculate theoretical voltage?
For emample, if you are dealing with Copper and Zinc, you first take the half equations Cu2+ + 2e- --> Cu +0.34 Zn2+ + 2e- ---> Zn -0.76 then, you decide which one is reduced and which one is oxidized, the one with the more positive voltage is reduced, so in this case the copper is reduced. the overall reaction changes to Zn- ---> Zn2+ + 2e +0.76 Cu2+ + 2e- --> Cu +0.34 ---- Zn + Ni2+ ---> Ni + Zn2+ + 0.5 you add the voltages and get 0.5 as an experimental voltage
What is the overall voltage for a redox reaction with the half reactions Ag e Ag s and Cu s Cu2 2e?
The overall voltage for the redox reaction involving Ag and Cu is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode. Given the reduction potentials of Ag and Cu as 0.80 V and 0.34 V respectively, the overall voltage is 0.46 V, calculated as (0.34 V) - (0.80 V).
What is the standard reduction potential for the half reaction Zn2 plus plus 2e- equals Zn?
Zn2+ + 2e- <--> Zno -0.7618 V
What are the half reaction for galvanic cell with Zn and Ni electrodes?
Zn(s)-> Zn2+(aq)+2e- and Ni2+(aq) + 2e- ->Ni(s)
What is the overall voltage for a redox reaction with the half-reactions Mgs Mg2 2e- and Cu2 2e- Cus?
0.34-(-2.37)
What is the overall voltage for a redox reaction with the half-reactions Mg-> Mg+2 +2e- and Cu2+ +2e- -> Cu?
0.34-(-2.37)
What is the overall voltage for a redox reaction with the half-reactions Mg(s) Mg2 2e- and Cu2 2e- Cu(s)?
0.34-(-2.37)
What is the overall voltage for a redox reaction with the half-reactions Mg s Mg2 2e- and Cu2 2e- Cu s?
0.34 - (-2.37) you're welcome.
What is the overall voltage for a redox reaction with the half-reaction Mg s Mg2 2e- and Cu2 2e- Cu s?
0.34 - (-2.37) you're welcome.
What is the overall voltage for a redox reaction with the half reactions Ag e Ag and Cu2 2e?
0.80-0.34
Calculate the standard emf of a cell that uses the Mg Mg2 plus and Cu Cu2 plus half cell reactions at 25 degrees C?
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
How do you calculate theoretical voltage?
For emample, if you are dealing with Copper and Zinc, you first take the half equations Cu2+ + 2e- --> Cu +0.34 Zn2+ + 2e- ---> Zn -0.76 then, you decide which one is reduced and which one is oxidized, the one with the more positive voltage is reduced, so in this case the copper is reduced. the overall reaction changes to Zn- ---> Zn2+ + 2e +0.76 Cu2+ + 2e- --> Cu +0.34 ---- Zn + Ni2+ ---> Ni + Zn2+ + 0.5 you add the voltages and get 0.5 as an experimental voltage
Is an oxidation half-reaction A. Fe2 plus Fe3 plus plus e- B. Fe3 plus plus e- Fe2 plus C. Fe(s) Fe(l) D. Fe plus 2e- Fe2 plus?
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
If silver and copper are used to make a cell what half-reactions will occur for ag plus aq plus e- ag s e0 equals 0.80 v and for cu2 plus aq plus 2e- cu aq e0 equals 0.34 V?
In the cell, the half-reaction for silver will be Ag+ (aq) + e- -> Ag (s) with a standard reduction potential of +0.80 V. The half-reaction for copper will be Cu2+ (aq) + 2e- -> Cu (s) with a standard reduction potential of +0.34 V. The silver half-reaction will occur at the cathode, while the copper half-reaction will occur at the anode in the cell.
If iron and copper are used to make a cell what halfreactions will occur?
Cu2+(aq) + 2e- → Cu(s) and Fe(s) → Fe2+(aq) + 2e-
What is the overall voltage for a redox reaction with the half reactions Ag e Ag s and Cu s Cu2 2e?
The overall voltage for the redox reaction involving Ag and Cu is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode. Given the reduction potentials of Ag and Cu as 0.80 V and 0.34 V respectively, the overall voltage is 0.46 V, calculated as (0.34 V) - (0.80 V).
