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To calculate the volume of 15 g of CO2 (carbon dioxide) at standard temperature and pressure (STP), we first determine the molar mass of CO2, which is approximately 44 g/mol. Using the ideal gas law, we know that 1 mole of any gas occupies 22.4 liters at STP. Therefore, the volume of 15 g of CO2 can be calculated as follows: ( \text{Volume} = \left(\frac{15 \text{ g}}{44 \text{ g/mol}}\right) \times 22.4 \text{ L/mol} \approx 7.6 \text{ L} ). Thus, the volume of 15 g of CO2 is approximately 7.6 liters at STP.
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What volume of CO2 gas will be evolved at ntp by heating 7.3 g of magnesium hydrogen carbonate?
The volume is 1,1 mL.
What is the density of an object that has a volume of 15 cm3 and a mass of 78 g?
To calculate the density of an object, you can use the formula: density = mass/volume. Given that the mass is 78 g and the volume is 15 cm³, the density would be 78 g / 15 cm³ = 5.2 g/cm³. Therefore, the density of the object is 5.2 g/cm³.
What volume will 15 g of NH3 occupy at stp?
The volume of ammonia is 19,5 L.
What volume will 125 g of CO2 occupy?
It depends on temperature and pressure. Assuming 25.0ºC and 1.00 atmospheres then 125 g CO2 occupies 54.7 dm3.
Determine the density of each what objects - mass 15 g volume 2 cm?
Note that "cm" is not a volume, so I'll assume you mean "cm3". 15 / 2 = 7.5 gm/cm3
What volume of CO2 gas will be evolved at ntp by heating 7.3 g of magnesium hydrogen carbonate?
The volume is 1,1 mL.
When calcium carbonate is heated strongly carbon dioxide gas is released CaCO3CaO CO2 what is the volume of CO2 measured stpis produced if 15.2 grams of caco3 is heated?
The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CO2 is 44.01 g/mol. By using stoichiometry, you can calculate that 15.2 grams of CaCO3 would produce 6.51 grams of CO2. Using the ideal gas law, you can then convert the mass of CO2 to volume using its molar volume at STP (22.4 L/mol). The volume of CO2 produced would be around 3.32 liters.
If you have a density of 3 ml and a mass of 15 g what is the volume?
To find the volume, you divide the mass by the density. In this case, the volume would be 5 ml (15 g ÷ 3 ml).
What is the density of a pebble has a mass of 36 g volume of 15 cm3?
Density = mass/volume = 36/15 = 2.4 g per cm3
What is the density of an object that is mass 15 g volume 2cm3?
Mass = 15 gm Volume = 2 cubic cm Density = Mass/Volume = 15/2 = 7 and 1/2 or 7.5 g per cm3
What is the density of an object that has a volume of 15 cm3 and a mass of 78 g?
To calculate the density of an object, you can use the formula: density = mass/volume. Given that the mass is 78 g and the volume is 15 cm³, the density would be 78 g / 15 cm³ = 5.2 g/cm³. Therefore, the density of the object is 5.2 g/cm³.
What volume will 15 g of NH3 occupy at stp?
The volume of ammonia is 19,5 L.
What is the density of a substance if it has a mass of 60.00 g and displaces water from a volume of 15.0 ml?
You will mean 15 cc or cubic centimeter. The answer is 4g / cc ( 60 g divide 15 cc )
What is the volume in milliliters occupied by 89.2g CO2(g) at 37oC and 737 mmHg?
To find the volume of a gas using the ideal gas law formula PV = nRT, we need to know the molar mass of CO2 (44.01 g/mol) and convert grams to moles. Then we can rearrange the formula to solve for V (volume) using P (pressure), n (moles), R (gas constant), and T (temperature). After plugging in the values (P = 737 mmHg, T = 37°C + 273 = 310 K), we can calculate the volume occupied by 89.2g of CO2 gas.
How many moles of methane are required to produce 22g of CO2?
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
What volume will 125 g of CO2 occupy?
It depends on temperature and pressure. Assuming 25.0ºC and 1.00 atmospheres then 125 g CO2 occupies 54.7 dm3.
How do i solve this at constant pressure and temperature 30g of CO2 gas occupies a volume of 410mL. Determine the volume of 110g of CO2 in liters?
Under these conditions, the volume will be directly proportional to the number of moles. And the number of moles varies with the number of grams. 110 g/30 g = 3.67, so there are 3.67 x more moles in 110 g as there are in 30 g. And the volume will be 3.67 x greater or 3.67 x 410 ml = 1503 ml = 1.5 liters (to 2 significant figures)
