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What quantity of reactants remains after ignition of a mixture that contains 2 moles of C2H6 mixed with 1.6 moles of O2?
Balanced equation first. 2C2H6 + 7O2 -> 4CO2 +6H2O I suspect C2H6 of limiting the reaction. 2 moles C2H6 (1.6 moles O2/2 moles C2H6) = 1.6 moles O2 left over and all of the C2H6 is consumed.
How many moles of C are in 32.6g of C2H6?
The answer is 2,17 moles carbon.
How many moles of C are in 32.6 g of C2H6?
To find the number of moles of carbon (C) in 32.6 g of ethane (C2H6), first calculate the molar mass of C2H6, which is approximately 30.07 g/mol. Since each molecule of C2H6 contains 2 moles of carbon, the total number of moles of C in 32.6 g of C2H6 can be found by dividing the mass by the molar mass and then multiplying by 2. This gives: [ \text{Moles of C} = \left(\frac{32.6 , \text{g}}{30.07 , \text{g/mol}}\right) \times 2 \approx 2.16 , \text{moles of C}. ]
How many moles of C2H6 are in 124 grams?
124 grams of ethane is equal to 4,124 moles.
How many grams of oxygen gas are required to completely react with 77.28 g of ethane (C2H6) in the balanced redox reaction 2 C2H6(g) 7 O2(g) 4 CO2(g) 6 H2O(g)?
To determine the grams of oxygen gas required to react with 77.28 g of ethane (C2H6), first calculate the moles of ethane. The molar mass of C2H6 is approximately 30.07 g/mol, so 77.28 g of C2H6 corresponds to about 2.57 moles of C2H6. According to the balanced reaction, 2 moles of C2H6 react with 7 moles of O2; thus, for 2.57 moles of C2H6, the required moles of O2 would be ( \frac{7}{2} \times 2.57 \approx 9.00 ) moles of O2. Finally, using the molar mass of O2 (approximately 32 g/mol), the mass of O2 needed is ( 9.00 , \text{mol} \times 32 , \text{g/mol} = 288 , \text{g} ).
What quantity of reactants remains after ignition of a mixture that contains 2 moles of C2H6 mixed with 1.6 moles of O2?
Balanced equation first. 2C2H6 + 7O2 -> 4CO2 +6H2O I suspect C2H6 of limiting the reaction. 2 moles C2H6 (1.6 moles O2/2 moles C2H6) = 1.6 moles O2 left over and all of the C2H6 is consumed.
How many moles of C are in 32.6g of C2H6?
The answer is 2,17 moles carbon.
How many moles of C are in 32.6 g of C2H6?
To find the number of moles of carbon (C) in 32.6 g of ethane (C2H6), first calculate the molar mass of C2H6, which is approximately 30.07 g/mol. Since each molecule of C2H6 contains 2 moles of carbon, the total number of moles of C in 32.6 g of C2H6 can be found by dividing the mass by the molar mass and then multiplying by 2. This gives: [ \text{Moles of C} = \left(\frac{32.6 , \text{g}}{30.07 , \text{g/mol}}\right) \times 2 \approx 2.16 , \text{moles of C}. ]
How many moles of C2H6 are in 124 grams?
124 grams of ethane is equal to 4,124 moles.
How many grams of oxygen gas are required to completely react with 77.28 g of ethane (C2H6) in the balanced redox reaction 2 C2H6(g) 7 O2(g) 4 CO2(g) 6 H2O(g)?
To determine the grams of oxygen gas required to react with 77.28 g of ethane (C2H6), first calculate the moles of ethane. The molar mass of C2H6 is approximately 30.07 g/mol, so 77.28 g of C2H6 corresponds to about 2.57 moles of C2H6. According to the balanced reaction, 2 moles of C2H6 react with 7 moles of O2; thus, for 2.57 moles of C2H6, the required moles of O2 would be ( \frac{7}{2} \times 2.57 \approx 9.00 ) moles of O2. Finally, using the molar mass of O2 (approximately 32 g/mol), the mass of O2 needed is ( 9.00 , \text{mol} \times 32 , \text{g/mol} = 288 , \text{g} ).
How many moles of carbon are there in 500 mole of c2h6?
The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor. 500 mol C2H6 x 2 mol C = 1000 mol C ........................1 mol C2H6
How many mols of co2 are formed in the equation 30c2h6 40o260co2 9h2o?
you need to label what unit you using in that equation, use proper capitalization, show whats being added to what and where the products and reactents are.
How many grams of oxygen gas will react with 77.28 grams of ethane in 2 C2H6 plus 7 O2 equals 4 CO2 plus 6H2O?
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
How many moles of HCl are present in 75 mL of a 200 M solution?
There are 15 moles of HCl present in 75 mL of a 200 M solution. To calculate this, first convert 75 mL to liters (0.075 L), then use the formula Molarity = moles/volume to find moles. So, 200 M = x moles / 0.075 L. Solving for x gives you 15 moles of HCl.
When 0.549 moles of a certain gas fill a balloon the volume is 75 mL. If enough of the same gas is added to the balloon until 1.44 moles of gas are present what is the new volume of the balloon?
The volume become 197 mL. (Avogadro law)
What is the molarity of a solution of sodium hydroxide if it contains 0.5 moles in 75mL of solution?
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.
How many moles of carbon dioxide can be produced from 1.00 mole of ethane?
7/2O2+C2H6->2CO2+3H2O Mole ratio of C2H6:CO2=1:2 No.of mole of CO2=2mol
