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In beta decay, a neutron in the nucleus transforms into a proton while emitting a beta particle (an electron) and an antineutrino. For the isotope 223/87 Fr (Francium), the beta decay equation can be represented as:
[ ^{223}{87}Fr \rightarrow ^{223}{88}Ra + \beta^- + \bar{\nu} ]
Here, Fr (Francium) decays into Ra (Radium) with the atomic number increasing by one, and a beta particle (β-) is emitted.
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What represents the formula that will balance this beta decay equation 24395 Am?
In beta decay, a neutron in the nucleus transforms into a proton while emitting a beta particle (electron) and an antineutrino. For the beta decay of americium-243 ((^{243}_{95}Am)), the balanced equation can be represented as: [ ^{243}{95}Am \rightarrow ^{243}{96}Cm + e^- + \bar{\nu}_e ] Here, (^{243}_{96}Cm) is curium-243, and (e^-) represents the emitted beta particle (electron).
What is the nuclear decay equation for selenium-75?
The nuclear decay equation for the decay of selenium-75 (75Se) by beta decay is: ( ^{75}{34}Se \rightarrow ^{75}{35}Br + e^- + \overline{\nu_e} ) This equation represents the transformation of a selenium-75 nucleus into a bromine-75 nucleus, an electron, and an electron antineutrino.
What is the balanced nuclear equation for the reaction in which zirconium-97 undergoes beta decay?
The equation for the beta decay of 137Cs:55137Cs --> 56137Ba + -10e where the e is a negative beta particle or electron.
How do you do nuclear decay equations?
To write nuclear decay equations, you would typically start with the parent nucleus and identify the type of decay (alpha, beta, gamma). Then, you would balance the equation by conserving mass number and atomic number on both sides of the equation. Finally, you write the decay products. Remember to include the correct particles emitted during the decay process.
What is the equation for the beta decay of barium-140?
The beta decay of barium-140 involves a neutron turning into a proton, releasing an electron (beta particle) and an antineutrino. The equation for this decay is: 56^140Ba -> 57^140La + e^- + v̄_e
Ype the letter that represents the formula that will balance this beta decay equation?
An alpha decay equation consists of the nucleus of an atom splitting into two parts: an alpha particle (He atom) and the resulting atom. To balance this equation, make sure that the amount of protons and neutrons are even on both sides.
What is the nuclear decay equation for radium-288?
The equation for the beta decay of 24Na is: 1124Na --> 1224Mg + -10e where the e is a negative beta particle or electron.
What is the nuclear decay equation for zirconium-97?
The equation for the beta decay of 97Zr is: 4097Zr --> 4197Nb + -10e representing the beta particle as -10e.
What is the nuclear decay equation for potassium 40?
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
What is the nuclear decay equation for potassium-40?
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
What is the equation for beta decay?
Pb-212
What is the nuclear decay equation for silicon 32?
The equation for the beta decay of 32Si is: 1432Si --> 1532P + -10e where -10e represents a negative beta particle or electron.
What is the equation for beta decay of Po?
That depends on the isotope.
What represents the formula that will balance this beta decay equation 24395 Am?
In beta decay, a neutron in the nucleus transforms into a proton while emitting a beta particle (electron) and an antineutrino. For the beta decay of americium-243 ((^{243}_{95}Am)), the balanced equation can be represented as: [ ^{243}{95}Am \rightarrow ^{243}{96}Cm + e^- + \bar{\nu}_e ] Here, (^{243}_{96}Cm) is curium-243, and (e^-) represents the emitted beta particle (electron).
What is the nuclear decay equation for cesium 137?
The equation for the beta decay of 137Cs is: 55137Cs --> 56137Ba + -10e where the -10e is a negative beta particle or electron.
What is the nuclear decay equation for fluorine 17?
The equation for the beta decay of 17F: 917F --> 817O+ 10e + ve where the 10e is a positive beta particle or positron.
What shows a balanced nuclear equation for the beta decay pf potassium-42?
The balanced nuclear equation for the beta decay of potassium-42 is: ^42K -> ^42Ca + e^- + νe
