Fifteen molecules of glucose can be used to form polysaccharides, specifically starch or glycogen, through a process called polymerization. In this process, the individual glucose molecules undergo dehydration synthesis, where water is removed to link them together. The resulting macromolecule will consist of a long chain of glucose units, serving as an energy storage form in plants (starch) or animals (glycogen).
Six carbon dioxide molecules (CO2) are required to create one glucose molecule (C6H12O6) because carbon dioxide has one carbon per molecule, while glucose molecules have six carbons.
Nitrogen (N2) is the group 15 element that exists as diatomic molecules.
64 net...68 are produced overall but 2 ATP's are used in the reaction per molecule of glucose.
H2O2 has four nuclei (atoms) in one molecule. Therefore, it has 20 'atoms' in 5 molecules. H2O has three nuclei in one molecule. Therefore, there are 15 nuclei in 5 molecules of water. 20-15 = 5 Ans: 5!
The equivalent is 1,6.10e-15 moles.
If 15 glucoses are bonded together by glycosidic bonds, a polymer of the carbohydrate glucose will be formed known as a polysaccharide. The most common polysaccharide formed from glucose molecules is starch in plants or glycogen in animals.
Six carbon dioxide molecules (CO2) are required to create one glucose molecule (C6H12O6) because carbon dioxide has one carbon per molecule, while glucose molecules have six carbons.
Glucose stores about 15 times more energy than ATP. Glucose is a larger molecule that can be broken down through cellular respiration to produce more ATP molecules as an energy source for the cell.
Let's start by setting up an equation of what is going on chemically. Sucrose is a sugar dimer of 1 fructose and 1 glucose molecule, so: 1 Sucrose --> 1 Glucose + 1 Fructose So, what we need to do from here is calculate how many moles of glucose would be needed to make 1 microgram (ug). The atomic mass of glucose is 180.16 g/mol, so 1ug = .000001 g. 0.000001g divided by 180.16 g/mol = 5.55 X 10^9 moles. Avogadro's number is 6.02214 X 10^23 and represents how many molecules are in 1 mole of a substance. Multiply this number by the moles of glucose and we should get 3.34 X 10^15 molecules in 1 microgram of glucose. Since the decomposition of 1 molecule of sucrose liberates 1 molecule of glucose, we do not have to take into account stoichiometric ratios. So, we need 3.34X 10^15 molecules of sucrose to decompose to get the same number of molecules of glucose. If we divide this by 1 million, we get 3.34 x 10^9. This is the number of seconds that would be needed for the decomposition to take place. Divide that by 60 we get 5.57 X 10^7 minutes, divide by 60 again and we get 9.28 X 10^5 hours, divide by 24 and we get 38,684 days and finally divide by 365 to get just under 106 years!
15
The normal glucose concentration in urine ranges from 0 to 15 mg/dL. The glucose concentration in urine becomes zero when no glucose has spilled over into the urine.
i know it's higher than corresponding blood glucose concentration from 10 - 15%
Nitrogen (N2) is the group 15 element that exists as diatomic molecules.
15
360 calaries
64 net...68 are produced overall but 2 ATP's are used in the reaction per molecule of glucose.
9033212250000000000000000 molecules or, in scientific notation, 9.03321225 × 10^24 molecules. This is found by multiplying the number of moles by the number of molecules in a mole, which is avagadro's number, 6.0221415 × 10^23. The calculation is: 15 × (6.0221415 × 10^23)