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What mass of silver nitrate is needed to fully react with 10.0 grams of calcium chloride?
The mass of silver nitrate is 30,6 g.
How many grams of calcium oxide will remain after 12.25grams of calcium carbonate is completely decomposed?
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
Use the periodic table to answer this question. Decomposing calcium carbonate yields calcium oxide and carbon dioxide. What information is needed to calculate the mass of calcium oxide that can be pro?
To calculate the mass of calcium oxide produced from the decomposition of calcium carbonate, you need the molar masses of calcium carbonate (CaCO₃) and calcium oxide (CaO). Additionally, you must know the amount (in grams or moles) of calcium carbonate you are starting with. Using stoichiometry from the balanced chemical equation, you can determine the mass of calcium oxide that can be produced.
What is the molecular mass of calcium bicarbonate?
The molecular mass of calcium bicarbonate (Ca(HCO₃)₂) can be calculated by adding the atomic masses of its constituent elements. Calcium (Ca) has an atomic mass of approximately 40.08 g/mol, hydrogen (H) about 1.01 g/mol, carbon (C) about 12.01 g/mol, and oxygen (O) about 16.00 g/mol. Therefore, the molecular mass of calcium bicarbonate is approximately 162.11 g/mol.
What information is needed to calculate the mass of calcium oxide that can be produced from 4.7 kg of calcium carbonate?
To calculate the mass of calcium oxide that can be produced from 4.7 kg of calcium carbonate, you need the molar masses of both calcium carbonate (CaCO₃) and calcium oxide (CaO). Additionally, you need to know the balanced chemical equation for the decomposition of calcium carbonate, which is: CaCO₃ → CaO + CO₂. Using this information, you can determine the moles of calcium carbonate and then use stoichiometry to find the corresponding mass of calcium oxide produced.
How many grams of calcium hydride are needed to form 8.700 g of hydrogen?
The molar mass of calcium hydride is 42.094 g/mol. Each mole of calcium hydride produces 2 moles of hydrogen gas. First, calculate the number of moles of hydrogen gas produced by 8.700 g of hydrogen, then use stoichiometry to find the mass of calcium hydride required.
How many grams of calcium hydride are needed to form 8.800g of hydrogen?
The molar mass of calcium hydride (CaH2) is 42.09 g/mol. To calculate the moles of CaH2 needed to form 8.800 g of hydrogen, divide the given mass of hydrogen by the molar mass of hydrogen (2.016 g/mol) and then multiply by 2 to account for the 1:1 stoichiometry between CaH2 and H2. This will give you the moles of CaH2 required, which you can then convert to grams.
How many grams of calcium are required to react with 7.75 grams of water to produce calcium hydroxide and hydrogen gas?
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
What is the word equation of calcium with hydrochloric acid?
One gram atomic mass of calcium reacts with two gram molecular masses of hydrochloric acid to form one gram formula mass of calcium chloride and one gram molecular mass of diatomic hydrogen gas.
How many grams of sodium needed to produce 2.0 mole of hydrogen gas?
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
According to the law of conservation of mass how many atoms of calcium can react to produce more calcium?
The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction, only rearranged. This means that the number of calcium atoms present before the reaction must be the same as the number of calcium atoms present after the reaction. Therefore, if a certain number of calcium atoms react to produce more calcium, the total number of calcium atoms will remain the same.
What is mass of calcium carbonate is to be decomposed to obtain 4.4 gram of carbon dioxide in the reaction caco3-cao plus o2?
The equation given shows that each formula mass of calcium carbonate produces one formula mass of CO2. The gram formula masses of calcium carbonate and carbon dioxide are 100.09 and 44.01 respectively. Therefore, to produce 4.4 grams of carbon dioxide, 4.4(100.09/44.01), or 10 grams of calcium carbonate, to the justified number of significant digits, are needed.
Is the volume of the unknown mass needed to calculate the mass of calcium oxide?
No. you will know the volume of the unknown mass after you calculate the mass of ca0
What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution?
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
How many moles of hydrogen are needed to make 170000 g of ammonia?
170 kg = 170,000g NH3 = 170,000g / 17.0g/molNH3 = [10,000 molNH3] * 3moleH2 / 2moleNH3= 15,000 mole H2 needed to produce 170 kg NH3
What information is needed to calculate the mass of calcium oxide that can be produced frrom 4.7 kg of calcium carbonate?
To calculate the mass of calcium oxide produced from 4.7 kg of calcium carbonate, you need to know the molar mass of calcium carbonate (CaCO3) and calcium oxide (CaO), as well as the stoichiometry of the reaction between these two compounds. This information will allow you to determine the theoretical yield of calcium oxide that can be obtained from the given mass of calcium carbonate.
What mass of calcium oxide is produced by heating 25 moles of calcium carbonate?
The molar ratio between calcium carbonate and calcium oxide is 1:1. So, 25 moles of calcium carbonate will produce 25 moles of calcium oxide. The molar mass of calcium oxide is 56.08 g/mol, so the mass of calcium oxide produced will be 25 moles * 56.08 g/mol = 1402 g.
