The mass of silver nitrate is 30,6 g.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
The molecular mass of calcium bicarbonate (Ca(HCO₃)₂) can be calculated by adding the atomic masses of its constituent elements. Calcium (Ca) has an atomic mass of approximately 40.08 g/mol, hydrogen (H) about 1.01 g/mol, carbon (C) about 12.01 g/mol, and oxygen (O) about 16.00 g/mol. Therefore, the molecular mass of calcium bicarbonate is approximately 162.11 g/mol.
To find out how much calcium is needed to make 15.0 g of calcium oxide (CaO), you have to consider the molar ratio of calcium to calcium oxide. The molar mass of CaO is 56.077 g/mol, and the molar mass of Ca is 40.078 g/mol. This means that for every 1 mol of CaO, you need 1 mol of Ca. Calculate the number of moles of CaO in 15.0 g, then use the molar ratio to find the moles of Ca needed. Finally, convert the moles of Ca to grams to find out how much calcium is needed to make 15.0 g of CaO.
This value is 0,2 g hydrogen.
The molar mass of calcium hydride is 42.094 g/mol. Each mole of calcium hydride produces 2 moles of hydrogen gas. First, calculate the number of moles of hydrogen gas produced by 8.700 g of hydrogen, then use stoichiometry to find the mass of calcium hydride required.
The molar mass of calcium hydride (CaH2) is 42.09 g/mol. To calculate the moles of CaH2 needed to form 8.800 g of hydrogen, divide the given mass of hydrogen by the molar mass of hydrogen (2.016 g/mol) and then multiply by 2 to account for the 1:1 stoichiometry between CaH2 and H2. This will give you the moles of CaH2 required, which you can then convert to grams.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
One gram atomic mass of calcium reacts with two gram molecular masses of hydrochloric acid to form one gram formula mass of calcium chloride and one gram molecular mass of diatomic hydrogen gas.
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction, only rearranged. This means that the number of calcium atoms present before the reaction must be the same as the number of calcium atoms present after the reaction. Therefore, if a certain number of calcium atoms react to produce more calcium, the total number of calcium atoms will remain the same.
The equation given shows that each formula mass of calcium carbonate produces one formula mass of CO2. The gram formula masses of calcium carbonate and carbon dioxide are 100.09 and 44.01 respectively. Therefore, to produce 4.4 grams of carbon dioxide, 4.4(100.09/44.01), or 10 grams of calcium carbonate, to the justified number of significant digits, are needed.
No. you will know the volume of the unknown mass after you calculate the mass of ca0
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
170 kg = 170,000g NH3 = 170,000g / 17.0g/molNH3 = [10,000 molNH3] * 3moleH2 / 2moleNH3= 15,000 mole H2 needed to produce 170 kg NH3
To calculate the mass of calcium oxide produced from 4.7 kg of calcium carbonate, you need to know the molar mass of calcium carbonate (CaCO3) and calcium oxide (CaO), as well as the stoichiometry of the reaction between these two compounds. This information will allow you to determine the theoretical yield of calcium oxide that can be obtained from the given mass of calcium carbonate.
The molar ratio between calcium carbonate and calcium oxide is 1:1. So, 25 moles of calcium carbonate will produce 25 moles of calcium oxide. The molar mass of calcium oxide is 56.08 g/mol, so the mass of calcium oxide produced will be 25 moles * 56.08 g/mol = 1402 g.