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How Many Moles Of PCl5 Can Be Produced From 58.0 G Of Cl2 (and Excess P4)?
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
The reaction pcl5 cl3 cl2 has keq 1.5 10 3 at a certain temperature if pcl3 0.20 cl2 0.11 and pcl5 0.05 what is true about this reaction?
The reaction will proceed to the left. PCl5 will be formed. PCl3 will be consumed.
Do both fermentation and cellular respiration produce NADH during the Krebs Cycle?
calculate the percent yiel if 49 grams of PCL5 is obtained from the treatment of 33.9 grams of pcl5 with 19 grams cl2
Cl-Cl bond in Cl2?
The Cl-Cl bond in Cl2 is a covalent bond formed by the sharing of two electrons between two chlorine atoms. This bond is nonpolar due to the equal sharing of electrons, resulting in a symmetrical molecule. The bond length is around 198 picometers.
Why is it that diatomic molecules always form non polar covalent?
They do not. Diatomic molecules containing two atoms of the same elemnt are non-polar, for example Cl2 . When the atoms are of different elents then the bond may be polar depending on the difference in electronegativity, example HCl.
Are ch3ch2ch2ch2ch3 and ch3ch2ch2ch2ch2ch3 miscible Are CBr4 and H20 miscible Are cl2 and H20 miscible?
Yes, both ch3ch2ch2ch2ch3 and ch3ch2ch2ch2ch2ch3 are miscible since they are both alkanes with similar intermolecular forces. CBr4 and H2O are immiscible because CBr4 is nonpolar while H2O is polar, resulting in different intermolecular forces that prevent them from mixing. Cl2 and H2O are immiscible because Cl2 is a nonpolar molecule while H2O is polar, leading to differences in intermolecular forces that hinder their ability to mix.
How Many Moles Of PCl5 Can Be Produced From 58.0 G Of Cl2 (and Excess P4)?
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
What is the decomposition reaction for PCl5?
The decomposition reaction for PCl5 is represented as follows: PCl5 (s) → PCl3 (g) + Cl2 (g). This reaction involves the breaking down of solid phosphorus pentachloride (PCl5) into gaseous phosphorus trichloride (PCl3) and chlorine gas (Cl2). The reaction is endothermic, requiring energy input to break the bonds within the PCl5 molecule.
The reaction pcl5 cl3 cl2 has keq 1.5 10 3 at a certain temperature if pcl3 0.20 cl2 0.11 and pcl5 0.05 what is true about this reaction?
The reaction will proceed to the left. PCl5 will be formed. PCl3 will be consumed.
How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
What mass of PCl5 will be produced from the given masses of both reactants which is 839 moles of P4 and 316 moles of Cl2 Answer needs to be submitted in grams though please?
Our lower number of moles is .316 so we will use that. The total molar mass of PCl5 is 208.2. So we will multiply the lower number of moles by our total mass. .316mol X 208.2 g/mol = 65.8g <------ answer.
The reaction pcl3 g plus cl2 g pcl5 g has keq equals 300 at a certain temperature if pcl3 equals 0.15 cl2 equals 0.04 and pcl5 equals 1.5 what is true about this reaction?
The reaction will proceed to the right. 2 PCl3 will be consumed.
What is the balanced equation of phosphorus trichloride reacting with chlorine?
show you the balance reaction between water and phsphorous trichloride show you the balance reaction between water and phsphorous trichloride show you the balance reaction between water and phsphorous trichloride
What kind of molecule is Cl2 polar or non polar?
Halogen molecules are not polar.
Do both fermentation and cellular respiration produce NADH during the Krebs Cycle?
calculate the percent yiel if 49 grams of PCL5 is obtained from the treatment of 33.9 grams of pcl5 with 19 grams cl2
What mass of PCl 5 will be produced from the given masses of both reactants?
What mass of will be produced from the given masses of both reactants? 28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4 0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5 54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2 .7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30 This is about limiting reagents You need to use 2P + 5Cl2 --> 2PCl5 [or P4 + 10Cl2 --> 4PCl5 if you prefer] that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react 69.3g
How many moles of PCl5 can be produced from 55.0 g of Cl2 (and excess P4)?
55.0 g of Cl2 contains 55.0/35.45* or 1.551 gram atoms of chlorine. Each mole of PCl5 requires exactly 5 gram atoms of chlorine, as shown by the formula. Therefore, 1.551/5.000 or 0.310 moles of PCl5 can be formed, to the justified number of significant digits. *This number is the gram Atomic Mass of chlorine.
