To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
The reaction will proceed to the left. PCl5 will be formed. PCl3 will be consumed.
calculate the percent yiel if 49 grams of PCL5 is obtained from the treatment of 33.9 grams of pcl5 with 19 grams cl2
The Cl-Cl bond in Cl2 is a covalent bond formed by the sharing of two electrons between two chlorine atoms. This bond is nonpolar due to the equal sharing of electrons, resulting in a symmetrical molecule. The bond length is around 198 picometers.
They do not. Diatomic molecules containing two atoms of the same elemnt are non-polar, for example Cl2 . When the atoms are of different elents then the bond may be polar depending on the difference in electronegativity, example HCl.
Yes, both ch3ch2ch2ch2ch3 and ch3ch2ch2ch2ch2ch3 are miscible since they are both alkanes with similar intermolecular forces. CBr4 and H2O are immiscible because CBr4 is nonpolar while H2O is polar, resulting in different intermolecular forces that prevent them from mixing. Cl2 and H2O are immiscible because Cl2 is a nonpolar molecule while H2O is polar, leading to differences in intermolecular forces that hinder their ability to mix.
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
The decomposition reaction for PCl5 is represented as follows: PCl5 (s) → PCl3 (g) + Cl2 (g). This reaction involves the breaking down of solid phosphorus pentachloride (PCl5) into gaseous phosphorus trichloride (PCl3) and chlorine gas (Cl2). The reaction is endothermic, requiring energy input to break the bonds within the PCl5 molecule.
The reaction will proceed to the left. PCl5 will be formed. PCl3 will be consumed.
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
Our lower number of moles is .316 so we will use that. The total molar mass of PCl5 is 208.2. So we will multiply the lower number of moles by our total mass. .316mol X 208.2 g/mol = 65.8g <------ answer.
The reaction will proceed to the right. 2 PCl3 will be consumed.
show you the balance reaction between water and phsphorous trichloride show you the balance reaction between water and phsphorous trichloride show you the balance reaction between water and phsphorous trichloride
Halogen molecules are not polar.
calculate the percent yiel if 49 grams of PCL5 is obtained from the treatment of 33.9 grams of pcl5 with 19 grams cl2
What mass of will be produced from the given masses of both reactants? 28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4 0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5 54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2 .7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30 This is about limiting reagents You need to use 2P + 5Cl2 --> 2PCl5 [or P4 + 10Cl2 --> 4PCl5 if you prefer] that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react 69.3g
55.0 g of Cl2 contains 55.0/35.45* or 1.551 gram atoms of chlorine. Each mole of PCl5 requires exactly 5 gram atoms of chlorine, as shown by the formula. Therefore, 1.551/5.000 or 0.310 moles of PCl5 can be formed, to the justified number of significant digits. *This number is the gram Atomic Mass of chlorine.