H, Mg, Zn, Cu
Zn + CuBr2 = Cu + ZnBr2
In this case, zinc will undergo oxidation and copper ions will experience reduction. The reduction half-reaction is Cu^2+ (aq) + 2e^- → Cu (s), and the oxidation half-reaction is Zn (s) → Zn^2+ (aq) + 2e^-. Overall, the reaction is Zn (s) + Cu^2+ (aq) → Zn^2+ (aq) + Cu (s).
Zn+CuSO4=Cu+ZnSO4 right?
Cu and Ga
During the replacement reaction of copper(II) nitrate (Cu(NO3)2) and zinc (Zn), zinc displaces copper, resulting in the formation of zinc nitrate (Zn(NO3)2) and elemental copper (Cu). The balanced equation for the reaction is: Zn + Cu(NO3)2 → Zn(NO3)2 + Cu. This reaction showcases a single displacement mechanism where a more reactive metal (zinc) replaces a less reactive metal (copper) in the compound.
Copper (Cu) is more active than nickel (Ni) and less active than zinc (Zn).
(Na, K, Ca, Mg, P, Fe, Cu, Zn, Mn and B
N, P, K, Fe, Mg, Zn, S, Cu etc.
The molecular equation for Cu(NO3)2 and Zn is Cu(NO3)2 + Zn -> Zn(NO3)2 + Cu. The total ionic equation is Cu^2+ + 2NO3- + Zn -> Zn^2+ + 2NO3- + Cu. The net ionic equation is Cu^2+ + Zn -> Zn^2+ + Cu.
Zn(s) --> Zn2+(aq) + 2e : Oxidation Cu+(aq) + 1e --> Cu(s) : Reduction
Zn + CuBr2 = Cu + ZnBr2
In this case, zinc will undergo oxidation and copper ions will experience reduction. The reduction half-reaction is Cu^2+ (aq) + 2e^- → Cu (s), and the oxidation half-reaction is Zn (s) → Zn^2+ (aq) + 2e^-. Overall, the reaction is Zn (s) + Cu^2+ (aq) → Zn^2+ (aq) + Cu (s).
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
Zn+CuSO4=Cu+ZnSO4 right?
Zn + CuSO4 --> ZnSO4 + Cu
Mg(s) + Zn(NO3)2 (aq) ---> Mg(NO3)2 (aq) + Zn(s)
The balanced equation for this reaction is: Zn(s) + Cu(NO3)2(aq) → Zn(NO3)2(aq) + Cu(s)