H, Mg, Zn, Cu
Zinc (Zn) commonly forms a +2 ion (Zn²⁺) due to the loss of two valence electrons. Magnesium (Mg) also typically forms a +2 ion (Mg²⁺) for the same reason. Copper (Cu) can form two types of ions: a +1 ion (Cu⁺) and a +2 ion (Cu²⁺), depending on the chemical environment and the compounds it forms.
Zn + CuBr2 = Cu + ZnBr2
In this case, zinc will undergo oxidation and copper ions will experience reduction. The reduction half-reaction is Cu^2+ (aq) + 2e^- → Cu (s), and the oxidation half-reaction is Zn (s) → Zn^2+ (aq) + 2e^-. Overall, the reaction is Zn (s) + Cu^2+ (aq) → Zn^2+ (aq) + Cu (s).
Zn+CuSO4=Cu+ZnSO4 right?
Cu and Ga
Copper (Cu) is more active than nickel (Ni) and less active than zinc (Zn).
(Na, K, Ca, Mg, P, Fe, Cu, Zn, Mn and B
N, P, K, Fe, Mg, Zn, S, Cu etc.
The molecular equation for Cu(NO3)2 and Zn is Cu(NO3)2 + Zn -> Zn(NO3)2 + Cu. The total ionic equation is Cu^2+ + 2NO3- + Zn -> Zn^2+ + 2NO3- + Cu. The net ionic equation is Cu^2+ + Zn -> Zn^2+ + Cu.
Zn(s) --> Zn2+(aq) + 2e : Oxidation Cu+(aq) + 1e --> Cu(s) : Reduction
Zn + CuBr2 = Cu + ZnBr2
In this case, zinc will undergo oxidation and copper ions will experience reduction. The reduction half-reaction is Cu^2+ (aq) + 2e^- → Cu (s), and the oxidation half-reaction is Zn (s) → Zn^2+ (aq) + 2e^-. Overall, the reaction is Zn (s) + Cu^2+ (aq) → Zn^2+ (aq) + Cu (s).
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
Zn+CuSO4=Cu+ZnSO4 right?
Zn + CuSO4 --> ZnSO4 + Cu
Mg(s) + Zn(NO3)2 (aq) ---> Mg(NO3)2 (aq) + Zn(s)
The balanced equation for this reaction is: Zn(s) + Cu(NO3)2(aq) → Zn(NO3)2(aq) + Cu(s)